Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 2)
2.
The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is:
Answer: Option
Explanation:
Clearly, the numbers are (23 x 13) and (23 x 14).
Larger number = (23 x 14) = 322.
Discussion:
153 comments Page 9 of 16.
Rajesh said:
1 decade ago
Read the question clearly.
Given that the two factors is 13 and 14 this means 23 is also a factor of L.C.M.
So LCM is 23*13*14.
Now 23 is HCF so suppose two numbers are 23*x and 23*y.
By theorem; (23*x)(23*y) = (23)(23*13*14).
This gives x equal to either 13 or 14 and similarly y.
Given that the two factors is 13 and 14 this means 23 is also a factor of L.C.M.
So LCM is 23*13*14.
Now 23 is HCF so suppose two numbers are 23*x and 23*y.
By theorem; (23*x)(23*y) = (23)(23*13*14).
This gives x equal to either 13 or 14 and similarly y.
Santhosh said:
1 decade ago
Very good explanations.
Sunil kumar said:
10 years ago
LCM*HCF = Value of that number.
So, HCF(LCM1) = n1.
HCF*LCM2 = n2.
So 23*13 = n1.
23*14 = n2.
N1<N2.
So, HCF(LCM1) = n1.
HCF*LCM2 = n2.
So 23*13 = n1.
23*14 = n2.
N1<N2.
Darshan said:
10 years ago
HCF means highest common factor.
LCM means least common Multiple.
Both are different. In this question they have given HCF of two numbers are 23.
Let us consider x and y as two no's then HCF (x, y) = 23.
We don't know the value of x and y. Then LCM of the two nos have factors 13 and 14.
This means that LCM (x, y) = z.
The value z have factors 13 and 14 which will divide z without leaving a remainder.
The main question is finding the larger of the two no is? That means we have to find biggest value among x and y.
I have understood the question but I don't how to solve it. I need clear explanation please.
LCM means least common Multiple.
Both are different. In this question they have given HCF of two numbers are 23.
Let us consider x and y as two no's then HCF (x, y) = 23.
We don't know the value of x and y. Then LCM of the two nos have factors 13 and 14.
This means that LCM (x, y) = z.
The value z have factors 13 and 14 which will divide z without leaving a remainder.
The main question is finding the larger of the two no is? That means we have to find biggest value among x and y.
I have understood the question but I don't how to solve it. I need clear explanation please.
Saurabh said:
10 years ago
Answer which is explained above assumes that the extra factors 13 and 14 are included in two separate numbers. The question does not say anything of this sort.
So technically, the correct answer is n1 = 23 and n2 = 23 x 13 x 14 = 4186.
You can verify that HCF = 23 and LCM = 2 x 7 x 13 x 23 = (2 x 7) x 13 x 23, for which the given statement that "The other two factors included in the LCM are 13 and 14" is perfectly valid.
So technically, the correct answer is n1 = 23 and n2 = 23 x 13 x 14 = 4186.
You can verify that HCF = 23 and LCM = 2 x 7 x 13 x 23 = (2 x 7) x 13 x 23, for which the given statement that "The other two factors included in the LCM are 13 and 14" is perfectly valid.
Vidyut said:
9 years ago
Please clear the concept easily.
Rasim said:
9 years ago
I'm little bit confuse in this concept. How we know to solve this ways. Please anybody is there to clear my doubt.
Sankar said:
9 years ago
Dear Friends,
Still I didn't understand the concept of LCM & HCF.
Please explain me in an easy way.
Still I didn't understand the concept of LCM & HCF.
Please explain me in an easy way.
Rose said:
9 years ago
I am confused with the question and method of solution. Can anyone help me?
Sameera said:
9 years ago
We have the terms HCF, LCM, product of 2 numbers (numbers be a,b).
In general,
Number = Factor * Factor.
eg :
6= 2*3 ----> 2, 3 factors of number 6.
8= 2*4-----> 2, 4 factors of 8.
So,
a = Factor * Factor.
b = Factor * Factor.
Here the 2 factors are 13, 14.
Given that, the highest common factor is 23,
So, we got another factor 23.
We require 4 factors to get a & b. But we have only 3.
And clearly said 23 is highest common factor.
Where 23 is a common factor in both a & b.
a = 23 * 13.
b = 23 * 14.
Therefore, the larger number = (23 x 14) = 322.
Hope you all understand this, if any mistake correct me.
In general,
Number = Factor * Factor.
eg :
6= 2*3 ----> 2, 3 factors of number 6.
8= 2*4-----> 2, 4 factors of 8.
So,
a = Factor * Factor.
b = Factor * Factor.
Here the 2 factors are 13, 14.
Given that, the highest common factor is 23,
So, we got another factor 23.
We require 4 factors to get a & b. But we have only 3.
And clearly said 23 is highest common factor.
Where 23 is a common factor in both a & b.
a = 23 * 13.
b = 23 * 14.
Therefore, the larger number = (23 x 14) = 322.
Hope you all understand this, if any mistake correct me.
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