Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 2)
2.
The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is:
276
299
322
345
Answer: Option
Explanation:

Clearly, the numbers are (23 x 13) and (23 x 14).

Larger number = (23 x 14) = 322.

Discussion:
153 comments Page 15 of 16.

Sachin alure said:   3 years ago
Well explained @Krishna.

JaGaDeeSh said:   3 years ago
Good explanation @Lahari.
(3)

Pratyusha 2 said:   3 years ago
Very helpful, thanks for explaining @Lahari.
(3)

Aditya uniyal said:   3 years ago
Please correct me, if I am wrong:

Let two numbers be A and B. It is given that their HCF is 23.

Therefore, A = 23 * x
and B = 23 * y, where x and y are coprime pairs, so according to the property of coprime LCM(x,y) = xy.

And we can find their LCM as follows: LCM(A, B) =LCM(23*x, 23*y) = 23 * x * y.

Therefore, x and y are the other two factors of LCM, and we are given that those 2 factors are 13 and 14 respectively.

Therefore x = 13 and y = 14.

And hence largest number = 23 * 14 = 322.
(63)

Hari bol said:   2 years ago
@All.

This question has a very clear concept of the fundamental theorem of arithmetic
Let one no. be =23a and the second no. =23b.

According to question;

First num. * Second num = hcf * lcm.
23a * 23b = 23 * lcm.

(Note the concept that HCF is always a factor of lcm )
So we can write;

23a* 23b= 23* 23* 13 * 14 ( as given in the question that 13 and 14 are the other factors )
so, ab = 13*14.

Now ACCORDING TO the FUNDAMENTAL THEOREM OF ARITHMETIC;

We need to express ab as the product of unique prime factors
ab = 13*7*2
Now, there can be 3 possible conditions
a can be
1. 13*7*2 ( then b will be 1) { note= you can do the same thing with b also there will be no change, only the last answer will be a=322}
2. 13*7 (then b will be 2)
3. 13 ( then b will be 14).

According to all the 3 conditions, the two numbers can be-
FOR 1nd condition.
first no. - 4186 ( 23a= 23 *13*7*2)
second no. - 23 (23b=23*1).

FOR 2nd condition.
First no. - 2743 (23a=23*13*7)
Second no. - 46 (23b = 23*2).

FOR 3 condition
First no. - 299 (23a = 23*13)
Second no. - 322 (23b=23*14)

So, if we see in the given question the options are given according to 3 condition
Hence, according to the 3rd condition, the greater number is b=322.
I hope it helps.
(58)

Guna said:   2 years ago
Good explanation. Thanks a lot @Hari Bol.
(6)

Anil said:   2 years ago
Good explanation, thanks.
(8)

Priyanshi said:   2 years ago
Very nice explanation. Thanks all.
(12)

Always krishna said:   1 year ago
HCF of two numbers is the number which is the common factor for both numbers given Here 23 is the common factor.
Other than this common factor, we also will have the product of uncommon factors for the two numbers (13 and 14 here).
The first number = 23 × 13 = 299 and
secondly number =23 × 14 = 322,
The greatest of two numbers is 23×14 = 322.
(46)

AyaanAmjad said:   1 year ago
Very helpful. Thanks all for giving the description.
(8)


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