Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 2)
2.
The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is:
Answer: Option
Explanation:
Clearly, the numbers are (23 x 13) and (23 x 14).
Larger number = (23 x 14) = 322.
Discussion:
153 comments Page 10 of 16.
Sunil kumar said:
10 years ago
LCM*HCF = Value of that number.
So, HCF(LCM1) = n1.
HCF*LCM2 = n2.
So 23*13 = n1.
23*14 = n2.
N1<N2.
So, HCF(LCM1) = n1.
HCF*LCM2 = n2.
So 23*13 = n1.
23*14 = n2.
N1<N2.
Prasanna Kartik said:
1 decade ago
Hi Guys,
My explanation is lets consider two numbers X, Y.
23 is the HCF of two numbers which means X and Y are exactly divisible by 23 in other words 23 is common factor for both the numbers so we can write X=23 X some value same as Y=23 X some value.
Then second part of the question if you see other remaining factors of LCM are 13 and 14 which means there is no common factors.
23|X , Y
|------
|13, 14
So X=23 X 13 and Y=23 X 14.
Correct me if I am wrong.
My explanation is lets consider two numbers X, Y.
23 is the HCF of two numbers which means X and Y are exactly divisible by 23 in other words 23 is common factor for both the numbers so we can write X=23 X some value same as Y=23 X some value.
Then second part of the question if you see other remaining factors of LCM are 13 and 14 which means there is no common factors.
23|X , Y
|------
|13, 14
So X=23 X 13 and Y=23 X 14.
Correct me if I am wrong.
(1)
Santhosh said:
1 decade ago
Very good explanations.
Rajesh said:
1 decade ago
Read the question clearly.
Given that the two factors is 13 and 14 this means 23 is also a factor of L.C.M.
So LCM is 23*13*14.
Now 23 is HCF so suppose two numbers are 23*x and 23*y.
By theorem; (23*x)(23*y) = (23)(23*13*14).
This gives x equal to either 13 or 14 and similarly y.
Given that the two factors is 13 and 14 this means 23 is also a factor of L.C.M.
So LCM is 23*13*14.
Now 23 is HCF so suppose two numbers are 23*x and 23*y.
By theorem; (23*x)(23*y) = (23)(23*13*14).
This gives x equal to either 13 or 14 and similarly y.
Hafizuddin said:
1 decade ago
Let 'a' and 'b' be the two numbers.
HCF (a, b) = 23.
LCM (a, b) = 13*a = 14*b (or) LCM = 14*a = 13*b.
Note : The (or) case is just to indicate that we could have taken the factors the other way round ---> since they are factors for LCM. Both cases would result in the same large number.
Theorem: The product of two numbers = a*b = LCM (a, b)*HCF (a, b).
Applying the above theorem here :
=> a*b = HCF (a, b)*LCM (a, b).
=> a*b = 23*(13*a) (or).
Therefore => b = 23*13.
Similarly, a = 23*14.
The largest of the 2 numbers = 23*14 = 322 is the answer.
HCF (a, b) = 23.
LCM (a, b) = 13*a = 14*b (or) LCM = 14*a = 13*b.
Note : The (or) case is just to indicate that we could have taken the factors the other way round ---> since they are factors for LCM. Both cases would result in the same large number.
Theorem: The product of two numbers = a*b = LCM (a, b)*HCF (a, b).
Applying the above theorem here :
=> a*b = HCF (a, b)*LCM (a, b).
=> a*b = 23*(13*a) (or).
Therefore => b = 23*13.
Similarly, a = 23*14.
The largest of the 2 numbers = 23*14 = 322 is the answer.
Sanjay said:
1 decade ago
I just want to know how these 13 and 14 obtained?
Viswanadha Ashok said:
1 decade ago
The L.C.M Of 2 numbers are (23x13) (23x14).
23x13 = 299, 23x14 = 322, which is largest number = 322.
23x13 = 299, 23x14 = 322, which is largest number = 322.
Vara said:
1 decade ago
We know that product of two numbers = H.C.F*L.C.M.
X*Y = H.C.F*L.C.M.
In the question they gave H.C.F of two numbers is 23. And the factors of their L.C.M are 13 and 14.
X*Y = H.C.F*L.C.M | check | L.C.M factors.
X*Y = 23*(13*14) |of two no's.
So |X = 23*13 = 299; |23|322, 299 ||14, 13.
Y = 23*14 = 322; ||.
So the greatest among the two no's is 322 |.
X*Y = H.C.F*L.C.M.
In the question they gave H.C.F of two numbers is 23. And the factors of their L.C.M are 13 and 14.
X*Y = H.C.F*L.C.M | check | L.C.M factors.
X*Y = 23*(13*14) |of two no's.
So |X = 23*13 = 299; |23|322, 299 ||14, 13.
Y = 23*14 = 322; ||.
So the greatest among the two no's is 322 |.
Manu said:
1 decade ago
We mean (Number = H.C.F*L.C.M) it's wrong or not please explain me.
Sallu said:
1 decade ago
First we have to understand the meaning of factor.
i.e. If number a is divided another number b exactly we say that a is factor of b.
Hence as per this factors are 13 and 14. So to find largest number.
Let us consider x and y are numbers.
x/factor = HCF.
y/factor = HCF.
x/13 = 23, x = 13*23 x = 299.
y/14 = 23, y = 14*23 y = 322.
So largest number is 322. Simple and less time consumption.
i.e. If number a is divided another number b exactly we say that a is factor of b.
Hence as per this factors are 13 and 14. So to find largest number.
Let us consider x and y are numbers.
x/factor = HCF.
y/factor = HCF.
x/13 = 23, x = 13*23 x = 299.
y/14 = 23, y = 14*23 y = 322.
So largest number is 322. Simple and less time consumption.
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