Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 9)
9.
The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:
1
2
3
4
Answer: Option
Explanation:

Let the numbers 13a and 13b.

Then, 13a x 13b = 2028

ab = 12.

Now, the co-primes with product 12 are (1, 12) and (3, 4).

[Note: Two integers a and b are said to be coprime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1 ]

So, the required numbers are (13 x 1, 13 x 12) and (13 x 3, 13 x 4).

Clearly, there are 2 such pairs.

Discussion:
94 comments Page 4 of 10.

Vinay ambidi said:   10 years ago
No someone asked why 5, 7 but if we multiply those numbers we will get 5*7 = 35.

That's why we have to take 1, 12 or 3, 4.

Shivang Dwivedi said:   2 years ago
@Veerbhadra.

Because (12*13, 13) and (13, 12*13) are considered as one unique pair, irrespective of the order of writing.
(2)

Siva said:   1 decade ago
@Arvind, you must not consider (26, 78) because then the HCF will become 26; as given in the question HCF must be only 13.

Nikhil G said:   5 years ago
@All.

1*12 = 1*3*2*2.
12*1 = 1*3*2*2.
2*6 = 3*2*2.
6*2 = 3*2*2.
3*4 = 3*2*2.
4*3 = 3*2*2.

So possible pairs are only 2.
(8)

Giri said:   1 decade ago
2 and 6 r not co-primes bcoz 6 has 2 as factor


whereas for 3 and 4 have no common factors except 1

RAHUL KUMAR SARASWAT said:   1 decade ago
Sir we have a formula that the product of two numbers= LCM * HCM.

Why this formula is not used in this question ?

Zoha said:   7 years ago
The product of two numbers is 2028 and their HCF is 13 find their LCM.
Ans: so, there LCM is 2 is that correct.

Swati said:   1 decade ago
Hey 13a*13b=2028 then a*b=156 if we take 13 common and divide it by 2028.

Then how it is written that a*b=12?

Deepak said:   1 decade ago
4 is definitely not prime number, then why you have taken as co prime?

Only one pair can be done i.e. 13, 1.

Madhu said:   4 years ago
(2, 6) are not co prime numbers.

As.
2=1*2.
6=1*6, 2*3;.

So for 6. (2) is again a factor so they can't be.
(1)


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