Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 9)
9.
The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:
Answer: Option
Explanation:
Let the numbers 13a and 13b.
Then, 13a x 13b = 2028
ab = 12.
Now, the co-primes with product 12 are (1, 12) and (3, 4).
[Note: Two integers a and b are said to be coprime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1 ]
So, the required numbers are (13 x 1, 13 x 12) and (13 x 3, 13 x 4).
Clearly, there are 2 such pairs.
Discussion:
94 comments Page 4 of 10.
Disha said:
8 years ago
Not getting this. Can anyone explain it to me?
SUDIP CHOUDHURY said:
8 years ago
LCM=2028/13=156 which means 13x12 or 12*13 so there are 2 ways.
(1)
Anik said:
8 years ago
Why not 2, 6? Please explain in clear.
Garima said:
8 years ago
Can we take a pair of 13, 1?
Klark said:
8 years ago
Why we can't use the pair (4, 3) & (12, 1). We are asked to find the total number of such pairs. So (1, 12), (3, 4), (4, 3), (12, 1)?
Jatin007 said:
8 years ago
Another way I'm telling you without co-primes.
2028/13=156, again divide 156/13 = 12.
Now factorize 12 = 1, 12, 3, 4.
There are 4 numbers so the pair is 2.
2028/13=156, again divide 156/13 = 12.
Now factorize 12 = 1, 12, 3, 4.
There are 4 numbers so the pair is 2.
Yashraj said:
8 years ago
I can't understand this. Please help me to get it.
Rbjii said:
9 years ago
Well, many of you got confused with Prime, co-Prime, why not (2,6) and all.....!!!
Lets we will Understood what's the question is ...!!!
The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:
step 1 : A * B = 2028 (Let A & B makes 2028 on multiply)
step 2 : (x*13) * (y*13) = 2028 (as mentioned HCF=13 for both A & B, so I took it as A=x*13, B=y*13)
******Note : HCF in the sense, only one number should be common in both A & B, hence it is 13 none other should be...!! ( are you cleared ??)*****
step 3 : x*y=2028/13*13
step 4 : x * y = 12 ( Product of X and Y makes 12, so we will separate 12 for and x & y)
*** The Sub-multiples of 12 are (1,12) (2,6) (3,4) .....still now ok...!! (Once again remember the NOTE..plzz)****
case 1 : (1,12)
A = 1 * 13
B = 12 * 13 (Product of A & B makes 2028, fine) also only 13 is common in both A & B. Hence it is satisfied
case 2 : (3,4)
A = 13 * 3
B = 13 * 4 ( Here also only 13 is common in both A & B. Hence this also satisfied )
case 3 : (2,6)
A = 13 * 2
B = 13 * 6(also 39 * 2 )
See clearly in both A and B the common numbers are 13 as well 2. It shouldn't be according to our NOTE
Hence this is not a correct pair with HCF as 13 alone. So it is said to not co-prime
JUST FOR UNDERSTANDING BIG DESCRIPTION..!! Paper Pen practice works faster ..!! ATB
Lets we will Understood what's the question is ...!!!
The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:
step 1 : A * B = 2028 (Let A & B makes 2028 on multiply)
step 2 : (x*13) * (y*13) = 2028 (as mentioned HCF=13 for both A & B, so I took it as A=x*13, B=y*13)
******Note : HCF in the sense, only one number should be common in both A & B, hence it is 13 none other should be...!! ( are you cleared ??)*****
step 3 : x*y=2028/13*13
step 4 : x * y = 12 ( Product of X and Y makes 12, so we will separate 12 for and x & y)
*** The Sub-multiples of 12 are (1,12) (2,6) (3,4) .....still now ok...!! (Once again remember the NOTE..plzz)****
case 1 : (1,12)
A = 1 * 13
B = 12 * 13 (Product of A & B makes 2028, fine) also only 13 is common in both A & B. Hence it is satisfied
case 2 : (3,4)
A = 13 * 3
B = 13 * 4 ( Here also only 13 is common in both A & B. Hence this also satisfied )
case 3 : (2,6)
A = 13 * 2
B = 13 * 6(also 39 * 2 )
See clearly in both A and B the common numbers are 13 as well 2. It shouldn't be according to our NOTE
Hence this is not a correct pair with HCF as 13 alone. So it is said to not co-prime
JUST FOR UNDERSTANDING BIG DESCRIPTION..!! Paper Pen practice works faster ..!! ATB
(5)
Sai ravi teja vallabhuni said:
9 years ago
Guys, 2 and 6 are not co-primes, that means 2 is divided only by 1 and 6 is divided by both 2 and 3.
Co primes are the numbers where they should be divided only by one, in this case, they are 3 and 4.
Co primes are the numbers where they should be divided only by one, in this case, they are 3 and 4.
Shobs said:
9 years ago
Only 2 pairs is correct. Know the meaning of co-prime first "two numbers are said to be coprime if their H.C.F is 1 "which suits only the (1, 12) and (3, 4) pairs.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers