Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 11)
11.
The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
Answer: Option
Explanation:
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x - 8) + (7x - 8) + (9x - 8) = 56
20x = 80
x = 4.
Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.
Discussion:
41 comments Page 4 of 5.
Pragathi said:
1 decade ago
Actually ago means past time so we have to add it's my doubt some times you will add some times you subtract please clarify it.
Neha said:
2 decades ago
How 20x comes?
Swetha said:
1 decade ago
Habib method is good:-).
Chenchu said:
1 decade ago
Can't understand habib's method of subracting 8 from b.
Ankit rathore said:
1 decade ago
Good explanation
Vissu said:
1 decade ago
Sum of there ages is 56 before 8 years then after 8 years it must be 64.
Virendra rajput said:
1 decade ago
Just look option which are having given ratio 4:7:9
A and D are ruled out then check 2"nd condition.
A and D are ruled out then check 2"nd condition.
Madhu said:
1 decade ago
Ago means we can subtract that given value, after means add that value.
Adinarayana said:
1 decade ago
Faruk explained detail but I didn't understand, how is it came 8, how did you take the 56+8+8+8.
Ronak said:
1 decade ago
The total of ratios is 20 (4+7+9).
The total of ages will become 56 + (8x3) = 56+24 = 80.
Now 20 x 4 = 80,
So the multiple is 4. So the common multiple is 4 for all.
Now we get present ages of all.
4x4 = 16.
7x4 = 28.
9x4 = 36.
The total of ages will become 56 + (8x3) = 56+24 = 80.
Now 20 x 4 = 80,
So the multiple is 4. So the common multiple is 4 for all.
Now we get present ages of all.
4x4 = 16.
7x4 = 28.
9x4 = 36.
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