Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 11)
11.
The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
8, 20, 28
16, 28, 36
20, 35, 45
None of these
Answer: Option
Explanation:

Let their present ages be 4x, 7x and 9x years respectively.

Then, (4x - 8) + (7x - 8) + (9x - 8) = 56

20x = 80

x = 4.

Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.

Discussion:
43 comments Page 4 of 5.

Chenchu said:   1 decade ago
Can't understand habib's method of subracting 8 from b.

Swetha said:   1 decade ago
Habib method is good:-).

Sumit said:   1 decade ago
@Habib method is good.

Pragathi said:   1 decade ago
Actually ago means past time so we have to add it's my doubt some times you will add some times you subtract please clarify it.

Ganesh said:   1 decade ago
Nice and easy method.

Payal said:   1 decade ago
Habib method was good

Shiva said:   1 decade ago
Shiva

(4x-8)+(7x-8)+(9x-8)= 56
Remove the braces.
4x-8+7x-8+9x-8 =56
Now seperate variables and numeric terms.
4x+7x+9x=56+8+8+8
20x=80
x=4.
njoy.

Rahima said:   1 decade ago
Just add all the x terms and numerical terms seperately.

JAGADEESH said:   2 decades ago
4x+7x+9x=80
20x=80
x=4
then we get answer

Habib said:   2 decades ago
For such ques......jst simply look at the options !!!!

Try subtracting 8 frm B...and den add u get 56 !!!!

Hit and Trial...saves time !!!! :)


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