Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 11)
11.
The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
Answer: Option
Explanation:
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x - 8) + (7x - 8) + (9x - 8) = 56
20x = 80
x = 4.
Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.
Discussion:
41 comments Page 3 of 5.
Andrew said:
6 years ago
@Swathi,
-8 because the total is calculated for 8 years ago.
-8 because the total is calculated for 8 years ago.
(1)
Rahima said:
1 decade ago
Just add all the x terms and numerical terms seperately.
Tanweer said:
7 years ago
8 year ago total age 56.
Now 8x3=24+56=80 answer is B.
Now 8x3=24+56=80 answer is B.
(1)
Chenchu said:
1 decade ago
Can't understand habib's method of subracting 8 from b.
Faruk said:
2 decades ago
4x+7x+9x = 56+8+8+8
20x = 80
is it simplified.
20x = 80
is it simplified.
Roshni said:
1 decade ago
It is a ratio of three values then why plus is coming?
Sanju said:
1 decade ago
4x-8+7x-8+9x-8=56 x=4 then 4x=16 is present ages.
(1)
Vinutha said:
1 decade ago
Simple method:
4*4 = 16.
7*4 = 28.
9*4 = 36.
4*4 = 16.
7*4 = 28.
9*4 = 36.
(1)
Vijay Anand said:
1 decade ago
@Anu.
AGO means(-).
SINCE, AFTER means(+).
AGO means(-).
SINCE, AFTER means(+).
JAGADEESH said:
1 decade ago
4x+7x+9x=80
20x=80
x=4
then we get answer
20x=80
x=4
then we get answer
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