Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 7)
7.
Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar's age at present?
Answer: Option
Explanation:
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
Then, | (6x + 6) + 4 | = | 11 |
(5x + 6) + 4 | 10 |
10(6x + 10) = 11(5x + 10)
5x = 10
x = 2.
Sagar's present age = (5x + 6) = 16 years.
Discussion:
128 comments Page 8 of 13.
Niranj said:
1 decade ago
@Faruk explained clearly, see it @Bhuvana.
Here we are calculating the present of Sagar, so instead of subtraction they used addition.
Here we are calculating the present of Sagar, so instead of subtraction they used addition.
Bhuvana said:
1 decade ago
In 6 years ago means -6 is comes why you have to use +6 in this equation?
Javid Mir said:
1 decade ago
Hi to all, the solution to this question goes like this;
Let the present age of Kunal & Sagar be "X" & "Y".
For Six years ago, X-6/Y-6 = 6/5....situation (1).
For Four years hence, X+4/Y+4 = 11/10....situation (2).
From situation (1) we will calculate value of "X".
5X-30 = 6Y-36 (On cross multiplication).
5X = 6Y-36+30.
5X = 6Y-6 => x = 6Y-6/5....equation (i).
Now from situation (2), we substitute the value value of "X" in situation (2):
10x6Y-6/5 + 40 = 11Y+44.
Dividing denominator "10" by "5" in numerator we get.
2x6Y-6 + 40 = 11Y+44.
12Y-12+40 = 11Y+44.
12Y-11Y = 44+12-40.
Y = 56-40.
Y = 16.
Let the present age of Kunal & Sagar be "X" & "Y".
For Six years ago, X-6/Y-6 = 6/5....situation (1).
For Four years hence, X+4/Y+4 = 11/10....situation (2).
From situation (1) we will calculate value of "X".
5X-30 = 6Y-36 (On cross multiplication).
5X = 6Y-36+30.
5X = 6Y-6 => x = 6Y-6/5....equation (i).
Now from situation (2), we substitute the value value of "X" in situation (2):
10x6Y-6/5 + 40 = 11Y+44.
Dividing denominator "10" by "5" in numerator we get.
2x6Y-6 + 40 = 11Y+44.
12Y-12+40 = 11Y+44.
12Y-11Y = 44+12-40.
Y = 56-40.
Y = 16.
Javid Mir said:
1 decade ago
Do it like this,
Let present age of Sagar & Kunal be "x" & "y".
Then, x-6/y-6 = 6/5....equation (1).
Similarly, x+4/y+4 = 11/10....equation (2).
From equation (1) on cross multiplication we get,
5x-30 = 6y-36.
5x = 6y-36+30.
5x = 6y-6.
x = 6y-6/5.
Substituting the value of "x" in equation....(2) we get.
10*(6y-6/5)+40 = 11y+44.
2*(6y-6)+40 = 11y+44.
12y-12+40 = 11y+44.
12y-11y = 44+12-40.
y = 16.
Let present age of Sagar & Kunal be "x" & "y".
Then, x-6/y-6 = 6/5....equation (1).
Similarly, x+4/y+4 = 11/10....equation (2).
From equation (1) on cross multiplication we get,
5x-30 = 6y-36.
5x = 6y-36+30.
5x = 6y-6.
x = 6y-6/5.
Substituting the value of "x" in equation....(2) we get.
10*(6y-6/5)+40 = 11y+44.
2*(6y-6)+40 = 11y+44.
12y-12+40 = 11y+44.
12y-11y = 44+12-40.
y = 16.
Swati singh said:
1 decade ago
As per concept you provided in ago we go for subtraction then how here addition of 6 done. Really I got confuse please help me.
Sindhu said:
1 decade ago
Let present ages of kunal and sagar be k and s respectively.
Then 6 years ago (k-6)/(s-6) = 5/6.
After 4 years (k+10/s+10) = 11/10.
After solving I got sagars age as 8 years. What wrong in this? Please help me.
Then 6 years ago (k-6)/(s-6) = 5/6.
After 4 years (k+10/s+10) = 11/10.
After solving I got sagars age as 8 years. What wrong in this? Please help me.
Hunt said:
1 decade ago
Let the 6 years ago ages was 6s & 5x;
Now at present; its ration is (6x+6)/(5x+5);
By next statement; 4 years hence; the age rations will become as; (6x+6+4)/(5x+6+4) = 11/10.
By its values x = 2;
Now as sagar's present age is = 5x+6 = 5*2+6 = 16 year;
Simple!
Now at present; its ration is (6x+6)/(5x+5);
By next statement; 4 years hence; the age rations will become as; (6x+6+4)/(5x+6+4) = 11/10.
By its values x = 2;
Now as sagar's present age is = 5x+6 = 5*2+6 = 16 year;
Simple!
Kanchana Pandian said:
1 decade ago
Lets take Kunal and Sagar's age as x & y.
6 years ago, x-6/y-6 = 6/5 --> 5x-6y+6 = 0 -> A.
4 years hence, x+4/y+4 +11/10 --> 10x-11y-4 = 0 ->B.
Solve A & B,
y(Sagars age) = 16.
6 years ago, x-6/y-6 = 6/5 --> 5x-6y+6 = 0 -> A.
4 years hence, x+4/y+4 +11/10 --> 10x-11y-4 = 0 ->B.
Solve A & B,
y(Sagars age) = 16.
Satheesh kumar said:
1 decade ago
They asked after four year, why we put the x=5. So we can add x=4. Answer me please.
Priyanka said:
1 decade ago
6 year ago means x-n.
Current age = 6x-(6 year ago).
6x-(-6)+4 == 6x+6+4.
Hope you guys understood :).
Current age = 6x-(6 year ago).
6x-(-6)+4 == 6x+6+4.
Hope you guys understood :).
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