Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 7)
7.
Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar's age at present?
Answer: Option
Explanation:
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
| Then, | (6x + 6) + 4 | = | 11 |
| (5x + 6) + 4 | 10 |
10(6x + 10) = 11(5x + 10)
5x = 10
x = 2.
Sagar's present age = (5x + 6) = 16 years.
Discussion:
128 comments Page 2 of 13.
Pallavi said:
8 years ago
Here consider There current ages x and y.
So according to 1 st condition.
X-6/y-6=6/5 --------> (1)
And according to 2 and Condition
X+4/y+4=11/10 --------> (2)
Solving (1) and (2) we get
10x-11y=4 --------> cross multiplication of (1)
5x-6y=-6 --------> cross multiplication of (2)
10x-11y=4 --------> (3)
So multiplying -2 (5x-6y=-6) we get;
-10x+12y=12 --------> (4).
Solving equations (3) and (4) we get;
y =16.
That is Sagar age.
So according to 1 st condition.
X-6/y-6=6/5 --------> (1)
And according to 2 and Condition
X+4/y+4=11/10 --------> (2)
Solving (1) and (2) we get
10x-11y=4 --------> cross multiplication of (1)
5x-6y=-6 --------> cross multiplication of (2)
10x-11y=4 --------> (3)
So multiplying -2 (5x-6y=-6) we get;
-10x+12y=12 --------> (4).
Solving equations (3) and (4) we get;
y =16.
That is Sagar age.
Resmi said:
2 years ago
6 : 5
11: 10.
The difference between two ratios ie 11-6= 5 10-5=5 both are 5.
So the ratio is balanced.
this difference represents the 10 yr gap 5--->10 yr.
10/5 =2.
Multiply this value by any given ratio.
if the ratio 6:5 is multiplied by 2 you will get the age of Kunal and Sagar 6yrs back.
ie 12 and 10 respectively.
So the present age of Sagar is 10 + 6 = 16.
11: 10.
The difference between two ratios ie 11-6= 5 10-5=5 both are 5.
So the ratio is balanced.
this difference represents the 10 yr gap 5--->10 yr.
10/5 =2.
Multiply this value by any given ratio.
if the ratio 6:5 is multiplied by 2 you will get the age of Kunal and Sagar 6yrs back.
ie 12 and 10 respectively.
So the present age of Sagar is 10 + 6 = 16.
(22)
Praveen said:
1 decade ago
Let the present of kunal=x ,& sagar =y.
Given 6 years ago their ratio is 6:5, here 6 years should be subtracted from their present age.
i.e.,
1) (x-6)/(y-6) = 6/5 -----(1).
Given 4 years later means nothing but 2 years ago from their present age (or) again they come back 4 years from ago 6 years.
2) (x-2)/(y-2) = 11/10 -----(2).
Solving (1) & (2) we get sagar age y=10.
After 6 years sagar age is,
y+6 = 10+6 = 16.
Given 6 years ago their ratio is 6:5, here 6 years should be subtracted from their present age.
i.e.,
1) (x-6)/(y-6) = 6/5 -----(1).
Given 4 years later means nothing but 2 years ago from their present age (or) again they come back 4 years from ago 6 years.
2) (x-2)/(y-2) = 11/10 -----(2).
Solving (1) & (2) we get sagar age y=10.
After 6 years sagar age is,
y+6 = 10+6 = 16.
Shariba riaz said:
8 years ago
It is clearly given that we have assumed the ages before six years and now we want the ages after 4 years of the present age. So we have to bring the ages to present age .so for that we have to add 6 to the ages that were before 6 years and we have to add 4 after that to calculate age after 5 years.
Ages before 6 years were 6x and 5x.
So present ages will be (6x+6)and (5x+6).
Ages after 4 years will be (6x+6)+4 and (5x+6)+ 4.
Ages before 6 years were 6x and 5x.
So present ages will be (6x+6)and (5x+6).
Ages after 4 years will be (6x+6)+4 and (5x+6)+ 4.
Javid Mir said:
1 decade ago
Do it like this,
Let present age of Sagar & Kunal be "x" & "y".
Then, x-6/y-6 = 6/5....equation (1).
Similarly, x+4/y+4 = 11/10....equation (2).
From equation (1) on cross multiplication we get,
5x-30 = 6y-36.
5x = 6y-36+30.
5x = 6y-6.
x = 6y-6/5.
Substituting the value of "x" in equation....(2) we get.
10*(6y-6/5)+40 = 11y+44.
2*(6y-6)+40 = 11y+44.
12y-12+40 = 11y+44.
12y-11y = 44+12-40.
y = 16.
Let present age of Sagar & Kunal be "x" & "y".
Then, x-6/y-6 = 6/5....equation (1).
Similarly, x+4/y+4 = 11/10....equation (2).
From equation (1) on cross multiplication we get,
5x-30 = 6y-36.
5x = 6y-36+30.
5x = 6y-6.
x = 6y-6/5.
Substituting the value of "x" in equation....(2) we get.
10*(6y-6/5)+40 = 11y+44.
2*(6y-6)+40 = 11y+44.
12y-12+40 = 11y+44.
12y-11y = 44+12-40.
y = 16.
Akhilkondaparva said:
9 years ago
Before 6 years Kunal's age is 6x.
After 6 years Kunal's age is 6x + 6.
Before 6 years Sagar's age is 5x.
After 6 years Sagar's age is 5x + 6.
Hence after 4 years from the present.
=> (6x + 6 + 4)/(5x + 6 + 4) = 11/10.
=> (6x + 10) * 10 = (5x + 10) * 11.
=> solving above we get x = 2.
Now Sagar's age at present is "5x + 6" right.
Therefore Sagar's age = 5 (2) + 6 = 16.
After 6 years Kunal's age is 6x + 6.
Before 6 years Sagar's age is 5x.
After 6 years Sagar's age is 5x + 6.
Hence after 4 years from the present.
=> (6x + 6 + 4)/(5x + 6 + 4) = 11/10.
=> (6x + 10) * 10 = (5x + 10) * 11.
=> solving above we get x = 2.
Now Sagar's age at present is "5x + 6" right.
Therefore Sagar's age = 5 (2) + 6 = 16.
Yash said:
6 years ago
My answer will be simple and easy.chexh this out:
6 years ago the ratio is 6x/5x(since a/b so we should take it as ax/bx).
Now the present ages are 6x+6/5x+6(since 6x/5x are the ages 6 years before),
After four years to the present age so (6x+6)+4/(5x+6)+4 = 11/10,
60x+100 = 55x+110,
5x = 10,
X = 2.
Since the present age of the second guy is 5x+6.
5(2)+6.
=16(final answer).
6 years ago the ratio is 6x/5x(since a/b so we should take it as ax/bx).
Now the present ages are 6x+6/5x+6(since 6x/5x are the ages 6 years before),
After four years to the present age so (6x+6)+4/(5x+6)+4 = 11/10,
60x+100 = 55x+110,
5x = 10,
X = 2.
Since the present age of the second guy is 5x+6.
5(2)+6.
=16(final answer).
(1)
Pallavi said:
5 years ago
@All.
By using the Ratio method:
K S (yrs)
6 : 5 ( -6).. 6 yrs ago so minus.
11 : 10 (+4)... After 4 yrs so add 4.
5 ratio = 10... The vertical difference between both the ratio is 5 i.e equal to the sum of the year (add yrs even if signs are different).
So, 1ratio = 2.
Then 2 * 5= 10 ... Sagar ratio is 5.
10+6= 16 yrs --- Add 6 for present age.
By using the Ratio method:
K S (yrs)
6 : 5 ( -6).. 6 yrs ago so minus.
11 : 10 (+4)... After 4 yrs so add 4.
5 ratio = 10... The vertical difference between both the ratio is 5 i.e equal to the sum of the year (add yrs even if signs are different).
So, 1ratio = 2.
Then 2 * 5= 10 ... Sagar ratio is 5.
10+6= 16 yrs --- Add 6 for present age.
Ana said:
9 years ago
Let us find the equation for 6 years ago.
x-6/y-6 = 6/5.
5(x-6)=6(y-6) ; 5x-30 = 6y-36 ; 5x-6y = -6-------- (1).
Let us find the equation for four years hence(later)
x+4/y+4 = 11/10.
10(x+4) = 11(y+4) ;10x+40 = 11y+44 ; 10x-11y= 4-------- (2)
Subtract eq (1)&(2).
10x-12y=-12 multiply by 2.
-10x+11y = -4.
----------------
Answer: y=16 Sagar present age.
x-6/y-6 = 6/5.
5(x-6)=6(y-6) ; 5x-30 = 6y-36 ; 5x-6y = -6-------- (1).
Let us find the equation for four years hence(later)
x+4/y+4 = 11/10.
10(x+4) = 11(y+4) ;10x+40 = 11y+44 ; 10x-11y= 4-------- (2)
Subtract eq (1)&(2).
10x-12y=-12 multiply by 2.
-10x+11y = -4.
----------------
Answer: y=16 Sagar present age.
Mubashshir said:
1 decade ago
No need to crack ur head just read the question, write the equation and solve it (question speaks itself)::
Ist condition :-
k-6/s-6 = 6/5 ..................I
IInd conditin :-
k+4/s+4 = 11/10 ...................II
so from I & II we got :-
k = 18
and s= 16 (required answer...)
Ist condition :-
k-6/s-6 = 6/5 ..................I
IInd conditin :-
k+4/s+4 = 11/10 ...................II
so from I & II we got :-
k = 18
and s= 16 (required answer...)
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