Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 7)
7.
Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar's age at present?
Answer: Option
Explanation:
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
Then, | (6x + 6) + 4 | = | 11 |
(5x + 6) + 4 | 10 |
10(6x + 10) = 11(5x + 10)
5x = 10
x = 2.
Sagar's present age = (5x + 6) = 16 years.
Discussion:
128 comments Page 11 of 13.
Shariba riaz said:
8 years ago
It is clearly given that we have assumed the ages before six years and now we want the ages after 4 years of the present age. So we have to bring the ages to present age .so for that we have to add 6 to the ages that were before 6 years and we have to add 4 after that to calculate age after 5 years.
Ages before 6 years were 6x and 5x.
So present ages will be (6x+6)and (5x+6).
Ages after 4 years will be (6x+6)+4 and (5x+6)+ 4.
Ages before 6 years were 6x and 5x.
So present ages will be (6x+6)and (5x+6).
Ages after 4 years will be (6x+6)+4 and (5x+6)+ 4.
Navin said:
8 years ago
You are right @Pradnya.
I understand it now, thank you.
I understand it now, thank you.
Sujitha Barmavath said:
8 years ago
Data is insufficient. When It says 'n' years ago then It should be written like 'x-n' but not 'x+n'. Formula itself says '-' for n years ago.
Nithi said:
8 years ago
In this question, why we add 4 to both numerator and denominator?
Bala said:
8 years ago
Guys, there is a shortcut for this method.
Let us take given options into consideration.
First, let's take option (a) that is 16 years (present age).
Given in the question that six years ago the ages of Kunal and Sagar is in the ratio (6:5) and we are asked to find the Sagar present age!
Hence 16-6 (six years ago) = 10.
10 is the multiple of 5 (Sagar age is 5x).
So condition one is satisfied.
In the next statement, they have given four years hence the ratio would be (11:10).
Meaning the Sagar's age is multiple of 10.
Hence (present age +four years).
We have taken option A into consideration that is 16.
So (16+4=20).
Which is a multiple of 10.
There you go both the conditions are satisfied and you have your answer.
Let us take given options into consideration.
First, let's take option (a) that is 16 years (present age).
Given in the question that six years ago the ages of Kunal and Sagar is in the ratio (6:5) and we are asked to find the Sagar present age!
Hence 16-6 (six years ago) = 10.
10 is the multiple of 5 (Sagar age is 5x).
So condition one is satisfied.
In the next statement, they have given four years hence the ratio would be (11:10).
Meaning the Sagar's age is multiple of 10.
Hence (present age +four years).
We have taken option A into consideration that is 16.
So (16+4=20).
Which is a multiple of 10.
There you go both the conditions are satisfied and you have your answer.
Prasanth kumar.G said:
8 years ago
it is clearly said that on above question 6 years ago means 6 years back so we subtract 6 from original ages;
So x-6/y-6 =6/5,
5x-30=6y-36,
then we have 5x-6y=-6--> (1)
As like they said hence after that means add 4 years from present;
So x+4/y+4=11/10,
10x+40=11y+44,
then we have 10x-11y=-4--> (2)
From 1 and 2 we can solve,
2 ( 5x-6y=-6)
10x-11y=-4 we can subtract
....................................
-y = -16 so clearly y = 16 Ans.
So x-6/y-6 =6/5,
5x-30=6y-36,
then we have 5x-6y=-6--> (1)
As like they said hence after that means add 4 years from present;
So x+4/y+4=11/10,
10x+40=11y+44,
then we have 10x-11y=-4--> (2)
From 1 and 2 we can solve,
2 ( 5x-6y=-6)
10x-11y=-4 we can subtract
....................................
-y = -16 so clearly y = 16 Ans.
Yillak said:
8 years ago
False answer because ago indicate minus and hence or later indicate plus.
Zard said:
8 years ago
Anwser is E.
Because the given ratio not verified.
let present age 16 years after five years 21 (16+5).
21 not multiple of 10.
and also 16 not multiple of 5.
Because the given ratio not verified.
let present age 16 years after five years 21 (16+5).
21 not multiple of 10.
and also 16 not multiple of 5.
Nishi Shukla said:
8 years ago
(x-6)/(y-6)=6/5 ---> i
(x+4)/(y+4)=11/10 ---> ii
By solving i and ii , we get y=16.
(x+4)/(y+4)=11/10 ---> ii
By solving i and ii , we get y=16.
Sharon said:
8 years ago
It is 6 years ago, then how you guys added it? kindly read it.
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