Aptitude - Problems on Ages - Discussion

it is clearly said that on above question 6 years ago means 6 years back so we subtract 6 from original ages;

So x-6/y-6 =6/5,
5x-30=6y-36,
then we have 5x-6y=-6--> (1)
As like they said hence after that means add 4 years from present;
So x+4/y+4=11/10,
10x+40=11y+44,
then we have 10x-11y=-4--> (2)
From 1 and 2 we can solve,
2 ( 5x-6y=-6)
10x-11y=-4 we can subtract
....................................
-y = -16 so clearly y = 16 Ans.

False answer because ago indicate minus and hence or later indicate plus.

Anwser is E.

Because the given ratio not verified.
let present age 16 years after five years 21 (16+5).
21 not multiple of 10.
and also 16 not multiple of 5.

(x-6)/(y-6)=6/5 ---> i
(x+4)/(y+4)=11/10 ---> ii
By solving i and ii , we get y=16.

It is 6 years ago, then how you guys added it? kindly read it.

How to add 4? please explain the step in detail.

Here consider There current ages x and y.
So according to 1 st condition.
X-6/y-6=6/5 --------> (1)

And according to 2 and Condition
X+4/y+4=11/10 --------> (2)

Solving (1) and (2) we get
10x-11y=4 --------> cross multiplication of (1)
5x-6y=-6 --------> cross multiplication of (2)
10x-11y=4 --------> (3)

So multiplying -2 (5x-6y=-6) we get;
-10x+12y=12 --------> (4).

Solving equations (3) and (4) we get;
y =16.
That is Sagar age.

6 years ago means we have to subtract as per the formula. Then why did they add in this problem?

Thanks @Faruk.

Well said @Neha.