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Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 5)
Problems on Ages
5.
Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?
24
27
40
Cannot be determined
None of these
Answer: Option
Explanation:

Let the present ages of Sameer and Anand be 5x years and 4x years respectively.

Then, 5x + 3 = 11
4x + 3 9

9(5x + 3) = 11(4x + 3)

45x + 27 = 44x + 33

45x - 44x = 33 - 27

x = 6.

Anand's present age = 4x = 24 years.

Discussion:
77 comments Page 6 of 8.
Kishan said:   1 decade ago
Can any one tell me how to read 4x and 5x. In both value we can assign same variable? Is it possible?
Deepthi said:   8 years ago
Can we do like this?

5x+3=11x
4x+3=9x
===>
20x+15=45x
20x+12=44x
===>
3=x

Is this right?
(1)
Murugan K said:   1 decade ago
5 years ago A age was 3 times as old as B . If A is 30years older than B .The present age of A?
Iti said:   1 decade ago
The total ages of the a, b and c 80 years. What was the total of their ages three year ago ?
Sai said:   1 decade ago
Given ratios :

5:4 and 11:9 now.
3x2 (difference of 11:9)/45-44(5*9-4*11).
= 6x4 = 24 .
Jyoti bala said:   1 decade ago
Why we take x for both?. May we take 2 different variables. I m not getting really.
Aarti dike said:   1 decade ago
3(11-9)/5*9-11*4 = 6.

Sameer and Anand present ratio is 5:4.

6*4 = 24.
Pratik said:   1 decade ago
x = ((11-9)*3)/(9*5-11*4).
So x = 6.

So Anand present age = 4*x = 24.
PAYAL said:   1 decade ago
Three year hence means AFTER THREE YEAR.

So, WE ADD 3 YEAR OK GUYS.
Irene said:   10 years ago
Please help me, I still don't understand. How we got 11/9?
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