Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 5)
5.
Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?
Answer: Option
Explanation:
Let the present ages of Sameer and Anand be 5x years and 4x years respectively.
Then, | 5x + 3 | = | 11 |
4x + 3 | 9 |
9(5x + 3) = 11(4x + 3)
45x + 27 = 44x + 33
45x - 44x = 33 - 27
x = 6.
Anand's present age = 4x = 24 years.
Discussion:
77 comments Page 3 of 8.
Vinay biranje said:
8 years ago
Sameer and Anand age ratio is 5:4.
After 3 years.
Sameer and Anand age ration is 11:9.
The diffrence between presnet and after age is 6 & 5.
After cross multiplying to the difference of ratios samerr age 5x = 5*5 = 25.
Anand age 4x =6*4 = 24.
That's it.
After 3 years.
Sameer and Anand age ration is 11:9.
The diffrence between presnet and after age is 6 & 5.
After cross multiplying to the difference of ratios samerr age 5x = 5*5 = 25.
Anand age 4x =6*4 = 24.
That's it.
Sonu said:
8 years ago
The ratio between presents ages of Pand Q is 3:4 respectively. If Q, s present age is 20 years, what will be the ratio of ages after 5 years?
Can anyone solve this?
Can anyone solve this?
(1)
Satish said:
8 years ago
Let me explain this in a simple procedure. The First ratio is 5:4.
We have to find Anand age after 3yrs.
Second ratio 11:9
So add 3 to both the numbers.y we r adding 3 is in question they gave after 3yrs
So the new ratio is 14:12
First ratio is 5:4.
New ratio is 14:12.
In this Anand age ratio is 4 AND 12.
Now check the option which is exactly divisible by both the numbers and that's the answer.
We have to find Anand age after 3yrs.
Second ratio 11:9
So add 3 to both the numbers.y we r adding 3 is in question they gave after 3yrs
So the new ratio is 14:12
First ratio is 5:4.
New ratio is 14:12.
In this Anand age ratio is 4 AND 12.
Now check the option which is exactly divisible by both the numbers and that's the answer.
(1)
Deepthi said:
8 years ago
Can we do like this?
5x+3=11x
4x+3=9x
===>
20x+15=45x
20x+12=44x
===>
3=x
Is this right?
5x+3=11x
4x+3=9x
===>
20x+15=45x
20x+12=44x
===>
3=x
Is this right?
(1)
Aman Chawla said:
8 years ago
Calculation can be reduced by using components and dividend which is applied on ratio's on both sides of equals.
Here is the method -> num1/den1 = num2=den2.
-> APPLYING COMPONENDO AND DIVIDENDO ON BOTH SIDES.
-> (num1+den1)/(num1-den1) = (num2+den2)/(num2-den2).
So here it goes,
(5x + 3) / (4x +3) = 11/9,
using above method it reduces to below in one go,
(9x + 6) / x = 10,
=> x = 6.
The requires answer then would be 4*x (using given ratio) is 24(answer).
Here is the method -> num1/den1 = num2=den2.
-> APPLYING COMPONENDO AND DIVIDENDO ON BOTH SIDES.
-> (num1+den1)/(num1-den1) = (num2+den2)/(num2-den2).
So here it goes,
(5x + 3) / (4x +3) = 11/9,
using above method it reduces to below in one go,
(9x + 6) / x = 10,
=> x = 6.
The requires answer then would be 4*x (using given ratio) is 24(answer).
JAISON said:
8 years ago
SHORTCUT METHOD.
Since they are asking ANAND's present age the ratio for Anands present age is 4.
So check the options which go for 4 table.
24 goes for 4 so 24 is the answer.
Suppose the ask Anand's age 3 years later the ratio is 9 so 3 years later his age will be 27 since 27 is divisible by 9.
Since they are asking ANAND's present age the ratio for Anands present age is 4.
So check the options which go for 4 table.
24 goes for 4 so 24 is the answer.
Suppose the ask Anand's age 3 years later the ratio is 9 so 3 years later his age will be 27 since 27 is divisible by 9.
Siddharth said:
8 years ago
@Srinath.
Let present ages of Ganguly and Sachin be x & y respectively.
Product of extremes = Product of means.
6(y-1)=7(x-1) &.
7(y+4)=8(x+4).
x= 31 and y= 36.
Let present ages of Ganguly and Sachin be x & y respectively.
Product of extremes = Product of means.
6(y-1)=7(x-1) &.
7(y+4)=8(x+4).
x= 31 and y= 36.
Vivek said:
8 years ago
Thanks for the given explanation.
Srinath said:
8 years ago
One year ago Ganguly and Sachin ages are in the ratio 6:7.4 years hence, the ratio of their ages will become 7:8. How old is Sachin?
Please give me the answer.
Please give me the answer.
Phataleakshaykumar said:
8 years ago
Let Nelson present age =3x and Michael present age =5x, After 9 years, so adding
(3x+9)/(5x+9) = (3/4).
x = 3.
m = 5x.
m = 5(3) = 15.
(3x+9)/(5x+9) = (3/4).
x = 3.
m = 5x.
m = 5(3) = 15.
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