Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 3)
3.
In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
Answer: Option
Explanation:
Total number of balls = (8 + 7 + 6) = 21.
| Let E | = event that the ball drawn is neither red nor green |
| = event that the ball drawn is blue. |
n(E) = 7.
| P(E) = |
n(E) | = | 7 | = | 1 | . |
| n(S) | 21 | 3 |
Discussion:
36 comments Page 4 of 4.
Romeo said:
3 years ago
Thanks all for explaining.
(4)
Vasu said:
1 decade ago
How the n(e) come as 7?
Anitha said:
8 years ago
How it is possible?
(1)
Nandini said:
1 decade ago
How n(E) =7?
Rohit said:
6 years ago
How n(E) =7?
Monika said:
1 decade ago
HOW n(E)=7?
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