Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 3)
3.
In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
1
3
3
4
7
19
8
21
9
21
Answer: Option
Explanation:

Total number of balls = (8 + 7 + 6) = 21.

Let E = event that the ball drawn is neither red nor green
= event that the ball drawn is blue.

n(E) = 7.

P(E) = n(E) = 7 = 1 .
n(S) 21 3

Discussion:
36 comments Page 4 of 4.

Romeo said:   1 year ago
Thanks all for explaining.
(1)

Vasu said:   1 decade ago
How the n(e) come as 7?

Anitha said:   7 years ago
How it is possible?

Nandini said:   1 decade ago
How n(E) =7?

Rohit said:   5 years ago
How n(E) =7?

Monika said:   1 decade ago
HOW n(E)=7?


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