# Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 3)

3.

In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

Answer: Option

Explanation:

Total number of balls = (8 + 7 + 6) = 21.

Let E | = event that the ball drawn is neither red nor green |

= event that the ball drawn is blue. |

*n*(E) = 7.

P(E) = | n(E) |
= | 7 | = | 1 | . |

n(S) |
21 | 3 |

Discussion:

36 comments Page 2 of 4.
Tharunteja said:
6 years ago

Guys it may be a wrong answer.

The actual correct answer;

Total no.of balls=(8+7+6)=21.

let E = event that the ball drawn is neither red nor green.

=event that the ball drawn is red/

Therefore n(E) = 8 (given neither red nor green) make a note this point.

therefore p(E) = 8/21.

The actual correct answer;

Total no.of balls=(8+7+6)=21.

let E = event that the ball drawn is neither red nor green.

=event that the ball drawn is red/

Therefore n(E) = 8 (given neither red nor green) make a note this point.

therefore p(E) = 8/21.

SRINU said:
10 years ago

Total balls-21.

7C1 = 7.

7/21.

7C1 = 7.

7/21.

Jaiprakash said:
8 years ago

@Obiano.

The answer is 1/2.

The answer is 1/2.

Ramachandran Nichite said:
8 years ago

Hi @Obiano.

Total ball = 5 + 3 + 2 = 10.

Choose yellow ball = 5/10.

Total ball = 5 + 3 + 2 = 10.

Choose yellow ball = 5/10.

Obiano kingseley said:
8 years ago

A bag contains 5yellow balls, 3green balls, and 2red balls, a ball is chosen at random from the bag. What is the probability that the chosen ball is yellow?

Can anyone answer this?

Can anyone answer this?

Faffy said:
8 years ago

Does this mean that we are excluding green and red?

Knowledgeispower said:
9 years ago

Using the same problem, solve for the probability of pulling a RED ball on 2 draws without replacing the ball after each draw.

Otuoboizy said:
9 years ago

Total numbers of balls is 21 and cl is 7.

S.Ranga reddy said:
1 decade ago

Hear there are 1 randomly selected means

green 8 blue 6

average of 2colors

so 8+6=14

14/2=7

green 8 blue 6

average of 2colors

so 8+6=14

14/2=7

Rajeev R T said:
1 decade ago

Event that the ball is neither red nor green, then you are left out with 7 blue balls, and out 7 blue balls you need one ball.

Then it is 7C1 ways... i.e = 7 ways.

Then it is 7C1 ways... i.e = 7 ways.

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