Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 3)
3.
In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
Answer: Option
Explanation:
Total number of balls = (8 + 7 + 6) = 21.
| Let E | = event that the ball drawn is neither red nor green |
| = event that the ball drawn is blue. |
n(E) = 7.
| P(E) = |
n(E) | = | 7 | = | 1 | . |
| n(S) | 21 | 3 |
Discussion:
36 comments Page 2 of 4.
Sree said:
1 decade ago
There is a die with 10 faces. It is not known that fair or not. 2 captains want to toss die for batting selection. What is the possible solution among the following?
a) If no. is odd it is head, if no. is even it is tail
b) If no. is odd it is tail, if no. is even it is head
c) Toss a die until all the 10 digits appear on top face. And if first no. in the sequence is odd then consider it as tail. If it is even consider it as head.
what is the exact solution
a) If no. is odd it is head, if no. is even it is tail
b) If no. is odd it is tail, if no. is even it is head
c) Toss a die until all the 10 digits appear on top face. And if first no. in the sequence is odd then consider it as tail. If it is even consider it as head.
what is the exact solution
Hina said:
1 decade ago
What is the meaning that die is fair or not?
Angamuthu SURESH said:
1 decade ago
Total number of balls = (8 + 7 + 6)
= 21.
Let E = event that the ball drawn is neither red nor green
=event that the ball drawn is red.
Therefore, n(E) = 8.
P(E) = 8/21.
= 21.
Let E = event that the ball drawn is neither red nor green
=event that the ball drawn is red.
Therefore, n(E) = 8.
P(E) = 8/21.
Farah said:
1 decade ago
Please all students read question carefully what he ask in question. He said that 8 red, 6 green, 7 blue total=21 probability ?
He said neither from red and green so only one option is 7 blue.
7c1 which is n(a)=7 and n(S)=21c1=21
Formula is prob. p(A)=n(A)/n(S)
7/21 = 1/3.
He said neither from red and green so only one option is 7 blue.
7c1 which is n(a)=7 and n(S)=21c1=21
Formula is prob. p(A)=n(A)/n(S)
7/21 = 1/3.
Muhammad Imran Tariq said:
1 decade ago
Sample= 8+7+6=21.
Probability of selection Red and Green= 8+6=14 / 21 = 2/3.
Not selection of Red and Green. Simple subtracts 1 from 2/3.
1 - 2/3= 1/3 (Answer).
Probability of selection Red and Green= 8+6=14 / 21 = 2/3.
Not selection of Red and Green. Simple subtracts 1 from 2/3.
1 - 2/3= 1/3 (Answer).
Mangesh Modiraj said:
1 decade ago
@Nandini & @Monica.
In example clearly mentioned that the ball ins neither red nor green.
i.e blue.
We have 7 blue balls.
Therefore n(E) = 7.
In example clearly mentioned that the ball ins neither red nor green.
i.e blue.
We have 7 blue balls.
Therefore n(E) = 7.
Bibekpangeni said:
1 decade ago
What is the meaning of probability?
Durga said:
1 decade ago
Total balls are - 21
So the probability of getting one ball is -21c1 = 21.
That one ball is neither red nor green means blue ball.
Posing one blue ball from 7 blue balls is 7c1 = 7.
Our required ans=7/21=1/3.
So the probability of getting one ball is -21c1 = 21.
That one ball is neither red nor green means blue ball.
Posing one blue ball from 7 blue balls is 7c1 = 7.
Our required ans=7/21=1/3.
SRINU said:
1 decade ago
Total balls-21.
7C1 = 7.
7/21.
7C1 = 7.
7/21.
Otuoboizy said:
10 years ago
Total numbers of balls is 21 and cl is 7.
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