Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 2)
2.
A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
10
21
11
21
2
7
5
7
Answer: Option
Explanation:

Total number of balls = (2 + 3 + 2) = 7.

Let S be the sample space.

Then, n(S) = Number of ways of drawing 2 balls out of 7
= 7C2 `
= (7 x 6)
(2 x 1)
= 21.

Let E = Event of drawing 2 balls, none of which is blue.

n(E) = Number of ways of drawing 2 balls out of (2 + 3) balls.
= 5C2
= (5 x 4)
(2 x 1)
= 10.

P(E) = n(E) = 10 .
n(S) 21

Discussion:
116 comments Page 9 of 12.

Tenzin said:   7 years ago
It's answers is 5/7.

1 1,1 2,2 1,3 1,3 2,

Five ways that we get the ball without getting a blue ball,
So it should be 5/7.

Pragya said:   7 years ago
C2 stands for what? Please explain me.

Trini said:   7 years ago
7c2 -> 7!/(7-2)! 2! which is 7*6*5!/5!2! = 7*6/2*1 = 21.

Ahmed said:   7 years ago
Simply, find the probability of getting 2 balls blue then subtract from 1.

Ritu verma said:   7 years ago
Prob of 1st ball not blue * prob of 2nd ball not blue.

= (5/7)*(4/6),
= 20/42,
= 10/21.

Shashikant sahu said:   7 years ago
This is a very simple technique.

1st ball not to be blue is = (1-2/7)=5/7.

Now next ball not to be blue is = (1-2/6)=4/6.
*(causes 1 ball has already taken).

Multiple both;

= 5/7 * 4/6.
= 10/21.

Harry said:   7 years ago
Can someone help me with this part of the question:

Let S be the sample space.

Then, n(S) = Number of ways of drawing 2 balls out of 7.
= 7C2 `
= (7 x 6).
(2 x 1),
= 21.

I don't understand what 7C2 means or how we get 7x6 or 2x1 then divided.
(2)

Manish Kumar Gupta said:   7 years ago
How come this 2c2/7c2?

Arnika said:   7 years ago
What is C and S please explain?

Christiano ronaldo said:   7 years ago
I didn't understand this. Please, anyone, help me to get it.


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