Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 2)
2.
A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
10
21
11
21
2
7
5
7
Answer: Option
Explanation:

Total number of balls = (2 + 3 + 2) = 7.

Let S be the sample space.

Then, n(S) = Number of ways of drawing 2 balls out of 7
= 7C2 `
= (7 x 6)
(2 x 1)
= 21.

Let E = Event of drawing 2 balls, none of which is blue.

n(E) = Number of ways of drawing 2 balls out of (2 + 3) balls.
= 5C2
= (5 x 4)
(2 x 1)
= 10.

P(E) = n(E) = 10 .
n(S) 21

Discussion:
117 comments Page 9 of 12.

Sarah said:   1 decade ago
The formula for ncr = n!/(n-r)!*r! if you submit values in this you can get the answer.

John said:   1 decade ago
Probability of occurrence of blue ball.

1 blue AND 1 blue OR,
1 red/green AND 1 blue OR,
1 blue AND 1 red/green.

(2/7 * 1/6) + (5/7 * 2/6) + (2/7 * 5/6) = 11/21.

Probability of non-occurrence of blue ball = 1-(11/21) = (10/21) ANS.

Hari said:   1 decade ago
Supriya c2 means multiply with number below it. Suppose 2c2= 2*1.

Bhavna said:   1 decade ago
I didn't understand the method which sagar did? can anybody make it clear!

Sundry said:   1 decade ago
From the explanation, where did 6 come from? why did you multiply 7 by 6? I did not understand that one.

Zuay said:   1 decade ago
No no no! I don't understand are we not suppose to consider probability of not obtaining blue balls here? then its 5/7.

Supriya said:   1 decade ago
How the (7*6)(2*1) has come?
Please clear my concept.

PRASHANT SINHA said:   1 decade ago
In the same question what is the probability of taking 2 blue balls?

Manjunath said:   1 decade ago
In the same question what is the probability of taking 2 blue balls?

Navcool said:   1 decade ago
Is it with or without replacement?


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