Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 2)
2.
A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
Answer: Option
Explanation:
Total number of balls = (2 + 3 + 2) = 7.
Let S be the sample space.
Then, n(S) | = Number of ways of drawing 2 balls out of 7 | |||
= 7C2 ` | ||||
|
||||
= 21. |
Let E = Event of drawing 2 balls, none of which is blue.
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= Number of ways of drawing 2 balls out of (2 + 3) balls. | |||
= 5C2 | ||||
|
||||
= 10. |
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n(E) | = | 10 | . |
n(S) | 21 |
Discussion:
116 comments Page 11 of 12.
Suyash said:
8 years ago
Simply, say 5/7 * 4/6.
= 10/21.
= 10/21.
Aman said:
8 years ago
@Jaani.
What is the probability of picking 2 blue ball then what is the probability?
What is the probability of picking 2 blue ball then what is the probability?
Tenzin said:
7 years ago
It's answers is 5/7.
1 1,1 2,2 1,3 1,3 2,
Five ways that we get the ball without getting a blue ball,
So it should be 5/7.
1 1,1 2,2 1,3 1,3 2,
Five ways that we get the ball without getting a blue ball,
So it should be 5/7.
Pragya said:
7 years ago
C2 stands for what? Please explain me.
Trini said:
7 years ago
7c2 -> 7!/(7-2)! 2! which is 7*6*5!/5!2! = 7*6/2*1 = 21.
Ahmed said:
7 years ago
Simply, find the probability of getting 2 balls blue then subtract from 1.
Ritu verma said:
7 years ago
Prob of 1st ball not blue * prob of 2nd ball not blue.
= (5/7)*(4/6),
= 20/42,
= 10/21.
= (5/7)*(4/6),
= 20/42,
= 10/21.
Shashikant sahu said:
7 years ago
This is a very simple technique.
1st ball not to be blue is = (1-2/7)=5/7.
Now next ball not to be blue is = (1-2/6)=4/6.
*(causes 1 ball has already taken).
Multiple both;
= 5/7 * 4/6.
= 10/21.
1st ball not to be blue is = (1-2/7)=5/7.
Now next ball not to be blue is = (1-2/6)=4/6.
*(causes 1 ball has already taken).
Multiple both;
= 5/7 * 4/6.
= 10/21.
Manish Kumar Gupta said:
7 years ago
How come this 2c2/7c2?
Arnika said:
7 years ago
What is C and S please explain?
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