Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 13)
13.
Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is:
3
20
29
34
47
100
13
102
Answer: Option
Explanation:

Let S be the sample space.

Then, n(S) = 52C2 = (52 x 51) = 1326.
(2 x 1)

Let E = event of getting 1 spade and 1 heart.

n(E) = number of ways of choosing 1 spade out of 13 and 1 heart out of 13
= (13C1 x 13C1)
= (13 x 13)
= 169.

P(E) = n(E) = 169 = 13 .
n(S) 1326 102

Discussion:
42 comments Page 3 of 5.

Naj said:   10 years ago
Why do we have to divide (52 x 51) by 2?

Farheen said:   9 years ago
P(c) = n(c)/n(s).
= 1/52 a king of hearts . Is it true?

Harish said:   9 years ago
Answer should be probability = 13/51.

Aisha said:   9 years ago
From where did 13 come? Can anyone explain? please.

Vineet pandey said:   9 years ago
Firstly see the question.

In a pack of 52 cards, there are 13 spades and 13 heart.
So, now according to question.

probability of getting 1 spades is =13c1 and same probability of getting heart is also 13c1
Here we write 13c1 because we have to pick a single(1) card out of total spade (13) and use same concept in heart.

Now (13c1 * 13c1 )/ 52c2.
So, the answer is 13/102.

52c2 is written here because there are total 52 cards out of which we pick two(2) card{ 1 of spade and 1 of heart } so that's why it is written as 52c2.
(1)

Ashish said:   9 years ago
Thanks @Vineet.

Uchenna said:   8 years ago
Does it mean that every pack must have 13 spade and 13 hearts?

VANAMALA SRINIVAS said:   8 years ago
No, the correct answer is 3/102.

Qaisara said:   8 years ago
I am unable to understand about 13. So anyone please explain me.

Rishit said:   7 years ago
@Ali and @Karim.

Here 2 cards are drawn TOGETHER. Which is why the 52c2. Your answer is correct for a scenario if the question was first drawn is club and second drawn is heart or vice versa.


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