Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 3)
3.
In how many different ways can the letters of the word 'CORPORATION' be arranged so that the vowels always come together?
Answer: Option
Explanation:
In the word 'CORPORATION', we treat the vowels OOAIO as one letter.
Thus, we have CRPRTN (OOAIO).
This has 7 (6 + 1) letters of which R occurs 2 times and the rest are different.
Number of ways arranging these letters = | 7! | = 2520. |
2! |
Now, 5 vowels in which O occurs 3 times and the rest are different, can be arranged
in | 5! | = 20 ways. |
3! |
Required number of ways = (2520 x 20) = 50400.
Video Explanation: https://youtu.be/o3fwMoB0duw
Discussion:
60 comments Page 4 of 6.
Rajmachawal said:
1 decade ago
Shouldn't there be a multiplication by 2fac in the end because there can be vowels first and then consonants or the consonants first and vowels second?
U. Sathish Reddy said:
10 years ago
You can do either of the way either consonants first or the vowels first.
Just separate the Word CORPORATION along with the vowels i.e
CRPRTN: These are 6 consonants, as are is repeated two times you need to divide it by 2!
Hence, 6+1 = 7!/2! = 5040/2 = 2520.
1 was from the set of vowels.
(OOAIO) - These are 5 vowels which is represented as 1 set.
Now, from the Vowels we get.
5!/3! = 120/6 = 20.
i.e 2520*20 = 50400.
Just separate the Word CORPORATION along with the vowels i.e
CRPRTN: These are 6 consonants, as are is repeated two times you need to divide it by 2!
Hence, 6+1 = 7!/2! = 5040/2 = 2520.
1 was from the set of vowels.
(OOAIO) - These are 5 vowels which is represented as 1 set.
Now, from the Vowels we get.
5!/3! = 120/6 = 20.
i.e 2520*20 = 50400.
Arun kumar said:
10 years ago
Which explanation is correct?
Ambrose said:
10 years ago
Given a set [ABCDEFGHIJKLMNOPQW]. In how many ways can we form a non repeated sub-set of 4-letter with letters (AB) being constant in every sub-set. Example [ABCE], [ABDC].
Vishnupriya said:
10 years ago
Find the number of ways in which an arrangement of four letter can be made from the letters of PRECIPITATION?
Please help me to solve this problem.
Please help me to solve this problem.
Aarti gupta said:
9 years ago
What is the difference between permutation and combination? I seriously can't understand the logic.
Aarti gupta said:
9 years ago
Is there someone who can help me out to understand the difference between both of them.
Bob said:
9 years ago
Where in question 3 does it indicate that only one vowel and only one consonant from the alphabet are permitted? Since this question appears to duplicate the wording of question 2, why isn't it solved in a like manner ? What am I missing here ?
Abhi said:
9 years ago
How come 7!/2! Is 2520? 7!/2! = (7*8) / (2*1) = 32 isn't? Then how 2520?
Abhi said:
9 years ago
@Aarthi,
The combination is selection only whereas permutation is selection + arrangement.
For example:
A committee should be formed with 2 persons from A, B, C, therefore, the should be {AB, BC, CA} only not {AB, BC, CA, BA, BC, CA} because AB and BA both are the same combination.
Next, If the question is like committee should be formed with one president and one vice president the answer is {AB, BC, CA, BA, BC, CA} because, in the combination AB, A can be president and B can be vice president and vice versa. So both are different.
The combination is selection only whereas permutation is selection + arrangement.
For example:
A committee should be formed with 2 persons from A, B, C, therefore, the should be {AB, BC, CA} only not {AB, BC, CA, BA, BC, CA} because AB and BA both are the same combination.
Next, If the question is like committee should be formed with one president and one vice president the answer is {AB, BC, CA, BA, BC, CA} because, in the combination AB, A can be president and B can be vice president and vice versa. So both are different.
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