Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 13)
13.
Gauri went to the stationers and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
Answer: Option
Explanation:
Let the amount taxable purchases be Rs. x.
| Then, 6% of x = | 30 |
| 100 |
 x = |
 |
30 | x | 100 |  = 5. |
| 100 | 6 |
Cost of tax free items = Rs. [25 - (5 + 0.30)] = Rs. 19.70
Discussion:
100 comments Page 9 of 10.
Naresh said:
1 decade ago
Let the amount taxable purchases be Rs. N.
Then, 6% of N =30/100
6/100 *N = 30/100 , then N=5.
Now we have to take the tax on 5Rs i.e.. 6%of 5.
That equals to , = (6/100)*5 = 0.30.
Therefore Cost of tax free items = Rs. [25 - (5 + 0.30)] = Rs. 19.70.
Then, 6% of N =30/100
6/100 *N = 30/100 , then N=5.
Now we have to take the tax on 5Rs i.e.. 6%of 5.
That equals to , = (6/100)*5 = 0.30.
Therefore Cost of tax free items = Rs. [25 - (5 + 0.30)] = Rs. 19.70.
Rohit jadaun said:
1 decade ago
Let x be the cost on which we are applying tax.
Then x*5/100=30/100 (30 paisa is now 30/100 rs).
x=5rs, on which we give tax.
And the tax is 0. 30rs.
So the total amount deducted will be 25- (5+0. 30) =19. 70.
Then x*5/100=30/100 (30 paisa is now 30/100 rs).
x=5rs, on which we give tax.
And the tax is 0. 30rs.
So the total amount deducted will be 25- (5+0. 30) =19. 70.
Jay said:
1 decade ago
@Scarlet.
Lets consider x is CP of chair and 400-x is CP of Table
(x*90/100)+((400-x)*110/100) = 400 *105/100.
Solve the above equation u vl get x=100.
So chair cost is 100.
Lets consider x is CP of chair and 400-x is CP of Table
(x*90/100)+((400-x)*110/100) = 400 *105/100.
Solve the above equation u vl get x=100.
So chair cost is 100.
Mini said:
1 decade ago
.30 is the actual tax paid not a part of the taxable portion which is rs.5.So .30 should not be included in the end of the solution.
Sachin said:
1 decade ago
Why do we add 0.30 at the last part? i Didn't understand.
Sangeetha said:
1 decade ago
Income of C is 20, 000.
20% of C = 10% of B.
So 20/100*20000=10/100*B.
We got B as 40000.
Then 5% of A = 15% of B.
5/100*A= 15/100*40000.
We got A as 120000.
Total is A+B+C=120000+40000+20000.
Total is 1, 80, 000/-.
20% of C = 10% of B.
So 20/100*20000=10/100*B.
We got B as 40000.
Then 5% of A = 15% of B.
5/100*A= 15/100*40000.
We got A as 120000.
Total is A+B+C=120000+40000+20000.
Total is 1, 80, 000/-.
Tarun said:
1 decade ago
5% of income of A is equal to 15% income of B and 10% of income of B is equal to 20% of income of C .if income of C is 20,000/-,then total income of A B C.
Sanjeev said:
1 decade ago
1. The first question can be solved in this way...
Take x as the price of chair n y as price of table.
2x+y=400 -eq1
Now with 10% loss in chair so subtract 0.1*2=0.2 from 2x and add 0.1 in y in Eq 1 and 5% profit in total so add 20 to 400
1.8x+1.1Y= 420 - eq2
Solve 1 and 2 eq we will get x as RS
50
Take x as the price of chair n y as price of table.
2x+y=400 -eq1
Now with 10% loss in chair so subtract 0.1*2=0.2 from 2x and add 0.1 in y in Eq 1 and 5% profit in total so add 20 to 400
1.8x+1.1Y= 420 - eq2
Solve 1 and 2 eq we will get x as RS
50
Vishal yadav said:
1 decade ago
20 is rite answer and according to ashish if you are giving sale tax 20000 then you have to pay agin tax of 20000 and again and again so on.
Nagapavan said:
1 decade ago
1.question not understand
2.1st 25lit alchol+5lit water
ratio 5:1
Taking 6 lit means 5lit alchol and 1lit water are taken out therefore 20lit alchol and 4 lit water are remaining after that 6lit water is filled
20/30*100=66.66%
2.1st 25lit alchol+5lit water
ratio 5:1
Taking 6 lit means 5lit alchol and 1lit water are taken out therefore 20lit alchol and 4 lit water are remaining after that 6lit water is filled
20/30*100=66.66%
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