Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 13)
13.
Gauri went to the stationers and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
Answer: Option
Explanation:
Let the amount taxable purchases be Rs. x.
| Then, 6% of x = | 30 |
| 100 |
 x = |
 |
30 | x | 100 |  = 5. |
| 100 | 6 |
Cost of tax free items = Rs. [25 - (5 + 0.30)] = Rs. 19.70
Discussion:
100 comments Page 3 of 10.
Vipul said:
10 years ago
Cost of stationary item is Rs. 25 which is included tax 30 paise.
So cost of item without tax is 25-0.30 = 24.70.
Now according to question let cost of item in which applying tax be X.
So 6% of X = 30/100 (because to convert paise into rupee divide by 100).
= 6/100*X = 30/100.
X = 5 rupees.
Now, cost of item with tax free = 24.70-5 = 19.70.
So cost of item without tax is 25-0.30 = 24.70.
Now according to question let cost of item in which applying tax be X.
So 6% of X = 30/100 (because to convert paise into rupee divide by 100).
= 6/100*X = 30/100.
X = 5 rupees.
Now, cost of item with tax free = 24.70-5 = 19.70.
Swaminathan Vembu said:
1 decade ago
If x is the total value of the amount paid.
Then 6 Percent of x = 30 paise as per the given data.
This implies 6/100 * x = 30 / 100 Rs.
Therefore x = 5Rs.
Adding 0.3 to 5 = 5.3 Rs = Total sales tax on all purchases.
Cost of all item (taxable + Non Taxable) = 25Rs.
Therefore amount paid on Non Taxable Items = 25-5.3 = 19.7Rs.
Then 6 Percent of x = 30 paise as per the given data.
This implies 6/100 * x = 30 / 100 Rs.
Therefore x = 5Rs.
Adding 0.3 to 5 = 5.3 Rs = Total sales tax on all purchases.
Cost of all item (taxable + Non Taxable) = 25Rs.
Therefore amount paid on Non Taxable Items = 25-5.3 = 19.7Rs.
Vinod Anand said:
1 decade ago
Bought things worth = Rs. 25.00.
Than 25 = 30*100/6.
=500/25 = 20.
When .30 paise went on sales tax on taxable purchases.
Than = 20-0.30 = 19.70 , Option (C).
or
6% of X = 30/100 ( when .30 Paisa = Rs.30/100).
Than x = 30*100/6*100 = 5.
Hence Rs. [25 - (5+.30)].
= 19.70 ,Option (C).
Than 25 = 30*100/6.
=500/25 = 20.
When .30 paise went on sales tax on taxable purchases.
Than = 20-0.30 = 19.70 , Option (C).
or
6% of X = 30/100 ( when .30 Paisa = Rs.30/100).
Than x = 30*100/6*100 = 5.
Hence Rs. [25 - (5+.30)].
= 19.70 ,Option (C).
Covindh said:
5 years ago
The answer is D becuase;
Given,
Total cost = Rs25 = Cost of non-taxable items + cost of taxable items = NT + T ----> eq.1
Now,
6% of cost of taxable items = Rs0.3.
Therefore, cost of taxable items = (100*0.3)/6 = Rs 5 = T.
From eq.1,
25 = NT + T.
25 = NT + 5.
Therefore, Cost of non-taxable items = Rs20 ----> Ans: D.
Given,
Total cost = Rs25 = Cost of non-taxable items + cost of taxable items = NT + T ----> eq.1
Now,
6% of cost of taxable items = Rs0.3.
Therefore, cost of taxable items = (100*0.3)/6 = Rs 5 = T.
From eq.1,
25 = NT + T.
25 = NT + 5.
Therefore, Cost of non-taxable items = Rs20 ----> Ans: D.
(1)
Ravi Kumar said:
5 years ago
The answer should be option D.
We get Rs. 5 as the number of taxable items which includes the tax of Rs 0.3.
Then why should we add that tax of Rs. 0.3 again in the last equation as Rs.5 contains the tax of Rs. 0.3 already.
Therefore, the cost of tax-free items should be = Rs.(25-5) = Rs.20.
Hope you all understood.
We get Rs. 5 as the number of taxable items which includes the tax of Rs 0.3.
Then why should we add that tax of Rs. 0.3 again in the last equation as Rs.5 contains the tax of Rs. 0.3 already.
Therefore, the cost of tax-free items should be = Rs.(25-5) = Rs.20.
Hope you all understood.
Ram said:
8 months ago
25rs = 2500p (1rs = 100p).
Totals spend = nontax item + tax item + tax = 2500p.
So, tax rate = 6% => 6% of (tax item) = 6% x (tax item) = tax
tax = 30p.
6/100 x (tax item) = 30p.
tax item = 3000/6 = 500p.
Then nontax item = total - tax item - tax = 2500 - 500 - 30 = 1970p,
Nontax item = 1970/100 = 19.7rs.
Totals spend = nontax item + tax item + tax = 2500p.
So, tax rate = 6% => 6% of (tax item) = 6% x (tax item) = tax
tax = 30p.
6/100 x (tax item) = 30p.
tax item = 3000/6 = 500p.
Then nontax item = total - tax item - tax = 2500 - 500 - 30 = 1970p,
Nontax item = 1970/100 = 19.7rs.
(30)
Sanjeev said:
1 decade ago
1. The first question can be solved in this way...
Take x as the price of chair n y as price of table.
2x+y=400 -eq1
Now with 10% loss in chair so subtract 0.1*2=0.2 from 2x and add 0.1 in y in Eq 1 and 5% profit in total so add 20 to 400
1.8x+1.1Y= 420 - eq2
Solve 1 and 2 eq we will get x as RS
50
Take x as the price of chair n y as price of table.
2x+y=400 -eq1
Now with 10% loss in chair so subtract 0.1*2=0.2 from 2x and add 0.1 in y in Eq 1 and 5% profit in total so add 20 to 400
1.8x+1.1Y= 420 - eq2
Solve 1 and 2 eq we will get x as RS
50
Bhanu said:
6 years ago
In the above question.
If whole 25 rupees is taxable then she would have paid 1.5rs tax i.e 150 paise because 6% of 25 is 1.5.
But she had only paid 30 paise i.e taxable amount of only 5 rupees.
So the total taxable amount is 5.3 rupees.. non-taxable amount is 19.70 rupees.
If whole 25 rupees is taxable then she would have paid 1.5rs tax i.e 150 paise because 6% of 25 is 1.5.
But she had only paid 30 paise i.e taxable amount of only 5 rupees.
So the total taxable amount is 5.3 rupees.. non-taxable amount is 19.70 rupees.
(2)
Manikanta said:
6 years ago
Here 25Rs includes(Non taxable amount+taxable amount+Sales Tax paid).
Tax rate is 6%on which tax paid is 30paise(30/100).
If 6% is 30/100, then for 100%(which is taxable amount) =?.
taxable amount=30paisa(or 30/100)*100/6=5rs.
So, Here 25 - (5 + 0.30) = 19.70 Is the answer.
Tax rate is 6%on which tax paid is 30paise(30/100).
If 6% is 30/100, then for 100%(which is taxable amount) =?.
taxable amount=30paisa(or 30/100)*100/6=5rs.
So, Here 25 - (5 + 0.30) = 19.70 Is the answer.
Dezal said:
9 years ago
In a class 60% of students passed in Telugu, 50% 0f students passed in English. Then if every student Passed in either Telugu or English or both the subjects. Then what is the percentage of students passed in both the subjects?
Can anyone help me to solve this problem?
Can anyone help me to solve this problem?
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