Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 9)
9.
A student multiplied a number by 3 instead of 5 .
5 3

What is the percentage error in the calculation?

34%
44%
54%
64%
Answer: Option
Explanation:

Let the number be x.

Then, error = 5 x - 3 x = 16 x.
3 5 15

Error% = 16x x 3 x 100 % = 64%.
15 5x

Discussion:
138 comments Page 8 of 14.

Suchita said:   1 decade ago
Error% = Error/True value.

But we have to calculate error value first.

So, Error = True value-False value.

Here, T.V = 5/3 & F.V = 3/5.

= 5/3-3/5, by solving this we get.

Error = 16/15.

Now, to calculate error%,

Error % = 16/15/5/3*100.

= 16/15*3/5*100 = 16/5*20.

= 64%.

Toini N Mutota said:   1 decade ago
I still didn't get it, how did you get the answer.

Secilia said:   1 decade ago
Still I did not get how you come up with 16/15. Maybe you can explain more.

Anusha said:   1 decade ago
I can't understand these problems. Is there any trick to solve the solution?

Michael said:   1 decade ago
Let the number be x.

Multiply by 3/5 = 3x/5 which is false.

True value 5/3 * x = 5x/3.

%error = [(true value - false value)/true value] * 100%.

= [(5x/3 - 3x/5)/(5x/3) ] * 100.

= [(16x/15)/(5x/3)] 100%.

= 16/25 * 100%.

= 64%.

Vengamanaidu said:   1 decade ago
Thank you @Michael, your explanation is the best method.

Vipin said:   1 decade ago
It's simple,

1. Let number be x
2. Error = true value - false value
3. 5/3 x - 3/5 = 16/15 x
4. We know the formula -> change = difference / initial value * 100

So, 16/15 x / 5/3 x *100 = 64 % -----> percentage we right because in question we say that error %.

Naveena said:   1 decade ago
Here,

True value = 5/3.
False value = 3/5.

To find the error => error = true value - false value.
=5/3 - 3/5.

Error = 16/15.

To find error % => error%= (error/true value) * 100.
=16/15 / 5/3 *100.

Error% = 64%.

Since, this is the simplification of this problem.

Gabriel said:   10 years ago
Two groups of students went into the shop. The first group bought four hot dogs and six juices and paid N$71.00 the second group bought three hotdogs and seven juices and paid N$67.00 what were the prices for these items (hotdog&juice)?

Can anyone solve this problem?

Triveni said:   10 years ago
@Chris It.

You clear my doubt. Thank you so much.


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