Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 9)
9.
| A student multiplied a number by | 3 | instead of | 5 | . |
| 5 | 3 |
What is the percentage error in the calculation?
Answer: Option
Explanation:
Let the number be x.
| Then, error = | 5 | x - | 3 | x = | 16 | x. |
| 3 | 5 | 15 |
| Error% = |  |
16x | x | 3 | x 100 |  % = 64%. |
| 15 | 5x |
Discussion:
134 comments Page 6 of 14.
Mahesha said:
7 years ago
How after 16x/15 * 3/5x * 100 it came 64%? Explain me. Please.
Ankit said:
7 years ago
5x/3-------> 16x/15 (error).
100--------> ?(error),
= 100 * (16x/15)/(5x/3).
100--------> ?(error),
= 100 * (16x/15)/(5x/3).
Ashutosh choudhury said:
7 years ago
X =15 ,
Because this number is divisible by both 3&5
5/3*15=25,
3/5*15=9,
The man should have got answer as 25 but he got 9,
So ,the difference is 25-9 =16,
If 25% of 100 then,
(16/25)*100 =64.
Because this number is divisible by both 3&5
5/3*15=25,
3/5*15=9,
The man should have got answer as 25 but he got 9,
So ,the difference is 25-9 =16,
If 25% of 100 then,
(16/25)*100 =64.
Shanmukh Adari said:
7 years ago
Thank you @Srihari.
Lee said:
7 years ago
Can anyone help me to understand the solution? please.
Lee said:
7 years ago
Question
A student divides the number by 3/4 when he is supposed to multiply the number by 4/3. What is the percentage of error in his answer?
A student divides the number by 3/4 when he is supposed to multiply the number by 4/3. What is the percentage of error in his answer?
Vaishu said:
7 years ago
Thank you @Srihari.
Ajit Singh rathore said:
7 years ago
There is two number is given x and y,
So first find the difference between this two no. Y-x=z,
And than for find % error,
We have to find what % of y in z,
Then;
Y/z*100.
So first find the difference between this two no. Y-x=z,
And than for find % error,
We have to find what % of y in z,
Then;
Y/z*100.
Raghava said:
7 years ago
I can't this. So, please explain me in a simple way.
Mohd Zeeshan said:
8 years ago
Thanks @Hari.
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