Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 9)
9.
A student multiplied a number by | 3 | instead of | 5 | . |
5 | 3 |
What is the percentage error in the calculation?
Answer: Option
Explanation:
Let the number be x.
Then, error = | 5 | x - | 3 | x = | 16 | x. |
3 | 5 | 15 |
Error% = | ![]() |
16x | x | 3 | x 100 | ![]() |
15 | 5x |
Discussion:
134 comments Page 2 of 14.
Naveena said:
9 years ago
Here,
True value = 5/3.
False value = 3/5.
To find the error => error = true value - false value.
=5/3 - 3/5.
Error = 16/15.
To find error % => error%= (error/true value) * 100.
=16/15 / 5/3 *100.
Error% = 64%.
Since, this is the simplification of this problem.
True value = 5/3.
False value = 3/5.
To find the error => error = true value - false value.
=5/3 - 3/5.
Error = 16/15.
To find error % => error%= (error/true value) * 100.
=16/15 / 5/3 *100.
Error% = 64%.
Since, this is the simplification of this problem.
Gabriel said:
9 years ago
Two groups of students went into the shop. The first group bought four hot dogs and six juices and paid N$71.00 the second group bought three hotdogs and seven juices and paid N$67.00 what were the prices for these items (hotdog&juice)?
Can anyone solve this problem?
Can anyone solve this problem?
Vipin said:
9 years ago
It's simple,
1. Let number be x
2. Error = true value - false value
3. 5/3 x - 3/5 = 16/15 x
4. We know the formula -> change = difference / initial value * 100
So, 16/15 x / 5/3 x *100 = 64 % -----> percentage we right because in question we say that error %.
1. Let number be x
2. Error = true value - false value
3. 5/3 x - 3/5 = 16/15 x
4. We know the formula -> change = difference / initial value * 100
So, 16/15 x / 5/3 x *100 = 64 % -----> percentage we right because in question we say that error %.
Zubi said:
4 years ago
First of all, we have to know the formulae;
Error = true value - false value.
Error% = error/true value.
Now solution:-
Here, Error = (5/3)-(3/5)=16/15
So, Error% = (error/true value)*100,
= {(16/15)/(5/3)}*100,
= 64%.
Error = true value - false value.
Error% = error/true value.
Now solution:-
Here, Error = (5/3)-(3/5)=16/15
So, Error% = (error/true value)*100,
= {(16/15)/(5/3)}*100,
= 64%.
(57)
Sandeep said:
7 years ago
We have multiplied a number by 3/5 instead of 5/3.
So, just find the difference between them,
5/3 - 3/5 = 16/15,
Now let's find out the error %,
For that, we have to take "the difference value" & "the multiplied value",
(16/15 * 3/5 * 100) = 64.
So, just find the difference between them,
5/3 - 3/5 = 16/15,
Now let's find out the error %,
For that, we have to take "the difference value" & "the multiplied value",
(16/15 * 3/5 * 100) = 64.
Lorance Mathew said:
1 decade ago
There is a rule.
(Numerator of 1st Fraction X Denominator of 2nd Fraction - Numerator of 2nd Fraction X Denominator of 1st Fraction)/(Denominator of 1st Fraction X Denominator of 2nd Fraction).
= (5 X 5 - 3 X 3)/(5 X 3) = (25 - 9)/15 .
= 16/15.
(Numerator of 1st Fraction X Denominator of 2nd Fraction - Numerator of 2nd Fraction X Denominator of 1st Fraction)/(Denominator of 1st Fraction X Denominator of 2nd Fraction).
= (5 X 5 - 3 X 3)/(5 X 3) = (25 - 9)/15 .
= 16/15.
Ashi said:
5 days ago
Take LCM of the denominator i.e 3 x 5 = 15.
3/5*15 = 9 (this is the number we mistakely multiplied)
(but the number should have been this all along ) 5/3 * 15 = 25.
Difference -> 25 - 9 = 16.
Now, 16/25(the right number)* 100 = 64%.
3/5*15 = 9 (this is the number we mistakely multiplied)
(but the number should have been this all along ) 5/3 * 15 = 25.
Difference -> 25 - 9 = 16.
Now, 16/25(the right number)* 100 = 64%.
Manikandan Kuppusamy said:
1 decade ago
Hi, I have one clarification.
Ques: A student multiplied a number by 3 instead of 6. What is the percentage error in the calculation?
As per above step,
We got 6x-3x = 3x, then.
3x*3x*100 = 900%. Is this correct? Please clarify me.
Ques: A student multiplied a number by 3 instead of 6. What is the percentage error in the calculation?
As per above step,
We got 6x-3x = 3x, then.
3x*3x*100 = 900%. Is this correct? Please clarify me.
Michael said:
9 years ago
Let the number be x.
Multiply by 3/5 = 3x/5 which is false.
True value 5/3 * x = 5x/3.
%error = [(true value - false value)/true value] * 100%.
= [(5x/3 - 3x/5)/(5x/3) ] * 100.
= [(16x/15)/(5x/3)] 100%.
= 16/25 * 100%.
= 64%.
Multiply by 3/5 = 3x/5 which is false.
True value 5/3 * x = 5x/3.
%error = [(true value - false value)/true value] * 100%.
= [(5x/3 - 3x/5)/(5x/3) ] * 100.
= [(16x/15)/(5x/3)] 100%.
= 16/25 * 100%.
= 64%.
Ashutosh choudhury said:
7 years ago
X =15 ,
Because this number is divisible by both 3&5
5/3*15=25,
3/5*15=9,
The man should have got answer as 25 but he got 9,
So ,the difference is 25-9 =16,
If 25% of 100 then,
(16/25)*100 =64.
Because this number is divisible by both 3&5
5/3*15=25,
3/5*15=9,
The man should have got answer as 25 but he got 9,
So ,the difference is 25-9 =16,
If 25% of 100 then,
(16/25)*100 =64.
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