Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 9)
9.
| A student multiplied a number by | 3 | instead of | 5 | . |
| 5 | 3 |
What is the percentage error in the calculation?
Answer: Option
Explanation:
Let the number be x.
| Then, error = | 5 | x - | 3 | x = | 16 | x. |
| 3 | 5 | 15 |
| Error% = |  |
16x | x | 3 | x 100 |  % = 64%. |
| 15 | 5x |
Discussion:
134 comments Page 2 of 14.
S.salman said:
1 decade ago
Thanks srihari.
Arun said:
1 decade ago
Thank you guys. Good analysis.
Rashmi said:
1 decade ago
But, still I'm not able to understand the logic for error %. Can any one describe it.
Saswat said:
1 decade ago
I m also unable to understand. Can you please make me understand. Is this formula is applicable to every situation ?
Pradip zala said:
1 decade ago
Suppose the no. is 300
Then error no. is 300*3/5 =180
and the actual answer is 300*5/3= 500
THE difference value is 320
Then ans is 320*100/500 = 64%
Then error no. is 300*3/5 =180
and the actual answer is 300*5/3= 500
THE difference value is 320
Then ans is 320*100/500 = 64%
Chitra said:
1 decade ago
I don't get it. Please any one tell me.
Sudershan said:
1 decade ago
We have to find error %.
percentage calculate from original value. So to find error percent
1.First v have to find the error.
2.Then percentage for error in original.
error = Original value - Wrong value.
= (5/3 x) - (3/5 x).
= 16/15 x
error% = error/original * 100;
= ((16/15 x) / (5/3 x)) * 100
= 64
So 64%
percentage calculate from original value. So to find error percent
1.First v have to find the error.
2.Then percentage for error in original.
error = Original value - Wrong value.
= (5/3 x) - (3/5 x).
= 16/15 x
error% = error/original * 100;
= ((16/15 x) / (5/3 x)) * 100
= 64
So 64%
Rawal said:
1 decade ago
Thanks Now I got it sudershan.
Abhiraj said:
1 decade ago
Thanks sudershan.
Durai said:
1 decade ago
Thanks durai.
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