Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 4)
4.
What percentage of numbers from 1 to 70 have 1 or 9 in the unit's digit?
Answer: Option
Explanation:
Clearly, the numbers which have 1 or 9 in the unit's digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.
Number of such number =14
 Required percentage = |
 |
14 | x 100 |  % = 20%. |
| 70 |
Video Explanation: https://youtu.be/cBamI6iRNIA
Discussion:
102 comments Page 2 of 11.
Joape said:
1 decade ago
It does not count 10, 12, 13, 14, 15, 16, 17, 18.
and they did not state about the square in the question.
and they did not state about the square in the question.
Naga said:
1 decade ago
I con't understad this problem
Daniel said:
1 decade ago
The question doesn't specify that the digits 1 or 9 must be the last digits, so clearly all the number in the teens, would qualitfy as nubers between 1 and 70 that have the digit 1 OR 9.
Avnish said:
1 decade ago
In every 10 digits there is 1 or 9 are coming,
So we can tell that what is the % of 2 out of 10,
That is 20 % only.
So we can tell that what is the % of 2 out of 10,
That is 20 % only.
RAVI TEJA ADARI said:
1 decade ago
Why should take ends with '1'?
Why not take other numbers?
Why not take other numbers?
Niraj said:
1 decade ago
What about 12,13,14,15,16,17,18?
Zaman said:
1 decade ago
We should first understand the question ?
The question asks the numbers with 1 or 9 in the unit digit that is in the last digit or ending with 1 or 9.
12, 13, 14 have 2, 3 and 4 in the unit digit respectively.
The question asks the numbers with 1 or 9 in the unit digit that is in the last digit or ending with 1 or 9.
12, 13, 14 have 2, 3 and 4 in the unit digit respectively.
Meena said:
1 decade ago
As per the given we should count only the digits which end with either 1 or 9(i.e, units place).
Suppose if we consider a no 527.
7 is in units place.
2 in tens place and.
5 is in Hundred's place.
In the same we get 1,9,11,19,21,29....so on 14 digits for the above question.
To be simple:
We have no's end with 1 = 7.
We have no's end with 9 = 7.
So total = 14.
Ans: 14/70*100 = 20%.
Suppose if we consider a no 527.
7 is in units place.
2 in tens place and.
5 is in Hundred's place.
In the same we get 1,9,11,19,21,29....so on 14 digits for the above question.
To be simple:
We have no's end with 1 = 7.
We have no's end with 9 = 7.
So total = 14.
Ans: 14/70*100 = 20%.
Siddharth said:
1 decade ago
Here's how it is done:
From 1 to 10---only 2 numbers have 1 & 9 at unit's place i.e.= 1 &9.
Therefore, from 10 to 20---11 and 19 have 1 & 9 at unit's place.
Then from 20 to 30---21, 29.
From 30 to 40---31, 39
From 60 to 70---61, 69.
So what concluded here is that each set has 2 numbers which have
1,9 at unit's place.
Therefore: 7 sets=2*7=total 14 numbers.
From 1 to 10---only 2 numbers have 1 & 9 at unit's place i.e.= 1 &9.
Therefore, from 10 to 20---11 and 19 have 1 & 9 at unit's place.
Then from 20 to 30---21, 29.
From 30 to 40---31, 39
From 60 to 70---61, 69.
So what concluded here is that each set has 2 numbers which have
1,9 at unit's place.
Therefore: 7 sets=2*7=total 14 numbers.
Raju said:
1 decade ago
25% of a number is less than 18% of 650 by 19. Then the number is?
Please send me the solution.
Please send me the solution.
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