Aptitude - Odd Man Out and Series - Discussion
Discussion Forum : Odd Man Out and Series - Odd Man Out (Q.No. 13)
Directions to Solve
Find the odd man out.
13.
41, 43, 47, 53, 61, 71, 73, 81
Answer: Option
Explanation:
Each of the numbers except 81 is a prime number.
Discussion:
61 comments Page 3 of 7.
Vijayalakshmi said:
8 years ago
What is a prime no?
@Murali.
How did you wrote the series of prime no. Can you explain it?
@Murali.
How did you wrote the series of prime no. Can you explain it?
Neha Sultan said:
9 years ago
It's 81.
That's because NO OTHER NUMBER IS PERFECTLY DIVISIBLE BY 3, EXCEPT 81.
That's because NO OTHER NUMBER IS PERFECTLY DIVISIBLE BY 3, EXCEPT 81.
Sunil said:
9 years ago
If we solve like that:
43 - 41 = 2,
47 - 43 = 4,
53 - 47 = 6,
61 - 53 = 8,
71 - 61 = 10,
73 - 71 = 2.
So, that 73 makes an error for the exact difference between the given numbers so according to me, 73 is an answer .
43 - 41 = 2,
47 - 43 = 4,
53 - 47 = 6,
61 - 53 = 8,
71 - 61 = 10,
73 - 71 = 2.
So, that 73 makes an error for the exact difference between the given numbers so according to me, 73 is an answer .
(1)
TANMOY said:
9 years ago
BUT why not 73 because its also not fit in series with 81? both are not fit isn't it?
Manav said:
9 years ago
Why its ans can't be 47?
41 4>1
43 4>3
47 4<7
53 5>3
61 6>1
71 7>1
73 7>3
81 8>1
Every 10th digit no is more than except 47, so the answer is 47. Why this answer is wrong?
41 4>1
43 4>3
47 4<7
53 5>3
61 6>1
71 7>1
73 7>3
81 8>1
Every 10th digit no is more than except 47, so the answer is 47. Why this answer is wrong?
Lakshman said:
9 years ago
Yes, I agree with Sandeep Shenoy.
Sandeep Shenoy said:
9 years ago
Answer 81 is correct. Because except 81, all other numbers are a prime number.
Amit said:
9 years ago
t = 41 + 2 * 1 = 43
t = 43 + 2 * 2 = 47
t = 47 + 2 * 3 = 53
t = 53 + 2 * 4 = 61
t = 61 + 2 * 5 = 71
t = 71 + 2 * 6 = 83.
In the given Series there 73 followed by 71, so the answer must be 73.
t = 43 + 2 * 2 = 47
t = 47 + 2 * 3 = 53
t = 53 + 2 * 4 = 61
t = 61 + 2 * 5 = 71
t = 71 + 2 * 6 = 83.
In the given Series there 73 followed by 71, so the answer must be 73.
Imran said:
9 years ago
3, 13, 31, 58, 91, 111 choose the wrong number in the series.
a) 58 b) 31 c) 91 d) 111.
Can anyone help me to solve this problem?
a) 58 b) 31 c) 91 d) 111.
Can anyone help me to solve this problem?
Murali said:
1 decade ago
All the numbers are prime numbers except 81.
Prime number series is 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997 etc.
Prime number series is 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997 etc.
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