Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 67)
67.
Which natural number is nearest to 9217, which is completely divisible by 88 ?
Answer: Option
Explanation:
On dividing we get,
88) 9217 (104
88
----
417
352
----
65
----
Therefore, Required number = 9217 + (88 - 65) // Because (88 - 65) < 65.
= 9217 + 23
= 9240.
Discussion:
13 comments Page 2 of 2.
Mahesh said:
6 years ago
Here, what they asked which natural no nearest 1 which div by 88.
Let's check the diff b/w option to 9217.
1.65
2.23
3. 153
4.33.
Among 2 is near to 9217.
Lets check B (9240) is div by 88 are not.
105 time of 88 gives 9240.
So, B is the right answer.
Let's check the diff b/w option to 9217.
1.65
2.23
3. 153
4.33.
Among 2 is near to 9217.
Lets check B (9240) is div by 88 are not.
105 time of 88 gives 9240.
So, B is the right answer.
(2)
Varad said:
4 years ago
Simple divide 9217 by 88 you will get 65 as the remainder.
Now, there are 2 cases;
Case 1) 9217 - 65 = 9152.
Case 2) 9217 + (88 - 65) = 9240/(88 - 65) to find difference.
The nearest number is 9240. So, that's the answer.
Now, there are 2 cases;
Case 1) 9217 - 65 = 9152.
Case 2) 9217 + (88 - 65) = 9240/(88 - 65) to find difference.
The nearest number is 9240. So, that's the answer.
(4)
SALEH said:
4 months ago
Decision rule:
If r<d/2 → nearest is below (subtract remainder).
If r>d/2 → nearest is above (add d−rd−r).
If r=d/2→ both are equally near,
Here,
88/2 = 44, 44<remainder 65,
So, 9217 + (88-65) = 9240,
Hence, the answer is 9240.
If r<d/2 → nearest is below (subtract remainder).
If r>d/2 → nearest is above (add d−rd−r).
If r=d/2→ both are equally near,
Here,
88/2 = 44, 44<remainder 65,
So, 9217 + (88-65) = 9240,
Hence, the answer is 9240.
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