Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 62)
62.
(51 + 52 + 53 + ... + 100) = ?
2525
2975
3225
3775
Answer: Option
Explanation:

Sn = (1 + 2 + 3 + ... + 50 + 51 + 52 + ... + 100) - (1 + 2 + 3 + ... + 50)

    = 100 x (1 + 100) - 50 x (1 + 50)
2 2

    = (50 x 101) - (25 x 51)

    = (5050 - 1275)

    = 3775.

Discussion:
19 comments Page 2 of 2.

Prithvi said:   7 years ago
Thanks all for explaining the answer.

Himanshu Soni said:   2 months ago
@All.

Here is an explanation;

(51+100),(52+99),(53+98),…

Each pair = 151.
Total numbers = 50.
Total pairs = 25.
So, 25 × 151 = 3775​.

Tanisha Rajak said:   5 years ago
Thanks guys for explaining this.

Janardhan jada said:   5 years ago
Thanks to all for explaining the answer.

Rupam Bhattacharjee said:   1 decade ago
You guys also can do that.........
51+52+53+.......+100
50/2(51+100)
=25*151
=3775 rule is n/2(first term+last term)=sum

NP said:   7 years ago
Here, n is number of turns
this ex. is (51 to 100 then n is 50 number).

Pooja said:   1 decade ago
n/2[firstnum + lastnum].
n = 50{totalnum}.

50/2[50+100].
= 25[151].
= 3775.

Rajkin hossain said:   1 decade ago
Look my friends
51+100=151
52+99=151
53+97=151

If we are following in that way then we have 25 times 151

So the ans is 25*151=3775.

Tanya Mazumdar said:   1 decade ago
Thanks for the right and easiest technique.


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