Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 106)
106.
If x and y are the two digits of the number 653xy such that this number is divisible by 80, then x + y = ?
Answer: Option
Explanation:
80 = 2 x 5 x 8
Since 653xy is divisible by 2 and 5 both, so y = 0.
Now, 653x is divisible by 8, so 13x should be divisible by 8.
This happens when x = 6.
x + y = (6 + 0) = 6.
Discussion:
23 comments Page 3 of 3.
Tanuja said:
1 decade ago
I think we have to consider 3xy according to divisibility condition for 8 if why is 0 then 3x0 if we substitute 2 in place of x then 320/8 gets satisfied.
Saurabh said:
1 decade ago
"Now, 653x is divisible by 8, So 53x should be divisible by 8".
But by the test of divisibility value for x is 6.
But for what about 2?
But by the test of divisibility value for x is 6.
But for what about 2?
Martin said:
1 decade ago
The answer is 6.
Let the number be 65300.
65300/80 = 816.25; this is not a whole number.
Try 816 x 80 = 65280 - not quite there so add 80.
65280+ 80 = 65360.
6 + 0 = 6.
Let the number be 65300.
65300/80 = 816.25; this is not a whole number.
Try 816 x 80 = 65280 - not quite there so add 80.
65280+ 80 = 65360.
6 + 0 = 6.
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