Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 16)
16.
If the number 517*324 is completely divisible by 3, then the smallest whole number in the place of * will be:
Answer: Option
Explanation:
Sum of digits = (5 + 1 + 7 + x + 3 + 2 + 4) = (22 + x), which must be divisible by 3.
x = 2.
Discussion:
52 comments Page 4 of 6.
Aravind said:
9 years ago
456*85 divisible by 3. Find the smallest whole digit number.
A. 10 b. 84 c. 12 d. 21.
Give me the answer of this question.
A. 10 b. 84 c. 12 d. 21.
Give me the answer of this question.
Phuntsho dorji said:
9 years ago
Why using addition symbol instead of multiplication?
Please anyone explain to me.
Please anyone explain to me.
Vishnu said:
8 years ago
Good, thanks @Nikitha.
Saravanan said:
8 years ago
@Aravind
456*85.
1. 4+5+6+x+8+5=28+x
2. 28+10(A is given option )=38/3=12.66 ஃ A is No
3. 28+84=112/3=37.333. No
4. 28+12=/3=13.33. No
5.28+21=16.33. No
Ans: None of those
But.
28+2=30/3=10. Ans is 2.
456*85.
1. 4+5+6+x+8+5=28+x
2. 28+10(A is given option )=38/3=12.66 ஃ A is No
3. 28+84=112/3=37.333. No
4. 28+12=/3=13.33. No
5.28+21=16.33. No
Ans: None of those
But.
28+2=30/3=10. Ans is 2.
(1)
Fufh said:
8 years ago
But we can add all numbers.
Dev said:
8 years ago
Let the two numbers be a and b(a>b)
So A. T. Q
a-b=1365-----> [ eq no(1)]
Also;
b)a (6
- 6b
_____
15
______
Therefore;
From above we can say
a-6b=15-----> [eq no(2)]
Solving both equations we get;
b= 270[as per required].
Thanks.
So A. T. Q
a-b=1365-----> [ eq no(1)]
Also;
b)a (6
- 6b
_____
15
______
Therefore;
From above we can say
a-6b=15-----> [eq no(2)]
Solving both equations we get;
b= 270[as per required].
Thanks.
Debashish said:
7 years ago
According to you guys if a number is divisible by another number then sum of its all digits also divisible. But it's not true in all cases.
e.g. The number is 625 which is divisible by 5. But if we add all its digits 6+2+5=13 which is not divisible by 5.
So this principle is wrong.
e.g. The number is 625 which is divisible by 5. But if we add all its digits 6+2+5=13 which is not divisible by 5.
So this principle is wrong.
(1)
Mridul said:
7 years ago
@All.
The rule which one is applied here is only applicable for 3, not for 4 or 5 etc.
The rule which one is applied here is only applicable for 3, not for 4 or 5 etc.
Surya said:
7 years ago
Well done @Nikitha.
Manu said:
7 years ago
Thank you @Nithya.
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