Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 7)
7.
(935421 x 625) = ?
575648125
584638125
584649125
585628125
Answer: Option
Explanation:

935421 x 625 = 935421 x 54 = 935421 x 10 4
2

= 935421 x 104 = 9354210000
24 16

= 584638125

Discussion:
35 comments Page 2 of 4.

R.V said:   1 decade ago
93542100*6.
935421*20.
935421*5.

We take multiply of 20 and 5 is 20/5 = 4.

"93542100/4".

Vignesh said:   1 decade ago
935421* (600+20+5).

935421*6 = 5612526 add two 0 in end 561252600. -----A.

935421*2 = 1870842 add one 0 in end 18708420. ------B.

935421*5 = 4677105. -----C.

A+B+C = 584638125.
(2)

Prema said:   1 decade ago
Simply you will multiply 935421 with 625.

Nitesh vatsa said:   10 years ago
Lucky digit method.

Cancel multiple of 9 and add the rest.

3+2+1 = 6.
6+2+5 = 13 = 1+3 = 4.
6*4 = 24, 2+4 = 6.

Now check lucky digit method for option.

1. Cancel all combination of nine.

Add the rest 5+8 = 13 = 1+3 = 4.

So correct answer is B.

Mili said:   9 years ago
How 2 power 4 comes in denominator?

Priyank said:   9 years ago
@Nitesh Vatsa.

Options B and D both have sum = 6.

Then which is the correct answer?
(1)

Raju said:   9 years ago
By logic.

9 + 3 + 5 + 4 + 2 + 1 * 6 + 2 + 5 = 24 + 13,
==> 2 + 4 * 1 + 3 = 6 x 4,
==> 24 = 2 + 4 = 6.

1. 5 + 7 + 5 + 6 + 4 + 8 + 1 + 2 + 5 = 43 => 4 + 3 = 7.
2. 5 + 8 + 4 + 6 + 3 + 8 + 1 + 2 + 5 = 42 => 4 + 2 = 6.

So, option 2 satisfy with the given expression.

Therefore, option 2 is the answer.
(3)

Sidharthan m said:   7 years ago
Please help me to solve this problem.

The sum and product of two numbers are 13 and 40 respectively. The sum of their reciprocal is?

Chinmayi said:   7 years ago
@Raju.

Option 4 also satisfy with given expression.
5+8+5+6+2+8+1+2+5 => 4+2 => 6.
Then how to choose the correct answer?
(2)

Udaya shankar s said:   7 years ago
How 10/2 comes will you please explain?


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