Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 5)
5.
1397 x 1397 = ?
Answer: Option
Explanation:
1397 x 1397 | = (1397)2 |
= (1400 - 3)2 | |
= (1400)2 + (3)2 - (2 x 1400 x 3) | |
= 1960000 + 9 - 8400 | |
= 1960009 - 8400 | |
= 1951609. |
Discussion:
55 comments Page 2 of 6.
Rishi said:
6 years ago
Nice explanations. Thanks all.
(4)
Sagar said:
6 years ago
@Aruna.
Easy, thanks for solving it.
Easy, thanks for solving it.
(2)
Deepmars said:
6 years ago
Good explanation, thanks @Pramod.
(2)
Sunil said:
1 decade ago
This method of converting the nmber to nearest whole and make all the calculation W.R.T (a^2-b^2).
I think, Cris Cross method is much simpler to all, as we start getting values from unit place so we dont have to find all the digits. Find one check the option, second number check the option, and so on..
1397
*1397
--------
(AL MULTIPICATION ARE DONE W.R.T LOWER NUMBER )
1) Unit place = 7*7 = 49 (put 9 in unit place and 4 as carry for next step)
(Observe the option, all have 9 in
unit place, so carry on for next
value.)
2) tens place = (7*9 + 9*7) = 63 + 63 + 4 = 130
(Put 0 in Tens place and 13 as carry for next step if required)
( the 4 in the addition comes from above step carry)
answer till now is 09
(Check the options.....only 2 are with this
digits, so step 3....)
3) hundreds place = (7*3 + 3*7 + 9*9) = 21 + 21 + 81 + 13 = 136
(13 is carry from privous step.)
(Again put 6 in 100's pace and 13 as carry
for nxt step.)
answer till this stage is 609
(check the options.... only one option
matching this number so no
more calculation)
answer is A.
eg : if digits are abcd * wxyz
1) here (d*z) gives unit place number.
2) (z*c + y*d)gives tens place number.
3) (z*b + x*d + y*c) gives hundred place number.
4) (z*a + w*d + y*d + x*c)gives thousand number.
(OBSERVE THE TRICK)
5) (y*a + w*c + x*b) given nxt number to left.
6) (x*a + w*b) give nxt number.
7) (w*a) gives last number.
(Please note when ever you get CARRY from one STEP please add That Carry to The Step Followed after that step)
e.g: if step 1 results 57 as the answer put 7 at unit place and carry 5 to 2 step, add this five to 2 step result and so on...
if the explanation look wierd or trouble some please google vedic maths, and the name of this method is criss cross method.
I think, Cris Cross method is much simpler to all, as we start getting values from unit place so we dont have to find all the digits. Find one check the option, second number check the option, and so on..
1397
*1397
--------
(AL MULTIPICATION ARE DONE W.R.T LOWER NUMBER )
1) Unit place = 7*7 = 49 (put 9 in unit place and 4 as carry for next step)
(Observe the option, all have 9 in
unit place, so carry on for next
value.)
2) tens place = (7*9 + 9*7) = 63 + 63 + 4 = 130
(Put 0 in Tens place and 13 as carry for next step if required)
( the 4 in the addition comes from above step carry)
answer till now is 09
(Check the options.....only 2 are with this
digits, so step 3....)
3) hundreds place = (7*3 + 3*7 + 9*9) = 21 + 21 + 81 + 13 = 136
(13 is carry from privous step.)
(Again put 6 in 100's pace and 13 as carry
for nxt step.)
answer till this stage is 609
(check the options.... only one option
matching this number so no
more calculation)
answer is A.
eg : if digits are abcd * wxyz
1) here (d*z) gives unit place number.
2) (z*c + y*d)gives tens place number.
3) (z*b + x*d + y*c) gives hundred place number.
4) (z*a + w*d + y*d + x*c)gives thousand number.
(OBSERVE THE TRICK)
5) (y*a + w*c + x*b) given nxt number to left.
6) (x*a + w*b) give nxt number.
7) (w*a) gives last number.
(Please note when ever you get CARRY from one STEP please add That Carry to The Step Followed after that step)
e.g: if step 1 results 57 as the answer put 7 at unit place and carry 5 to 2 step, add this five to 2 step result and so on...
if the explanation look wierd or trouble some please google vedic maths, and the name of this method is criss cross method.
(1)
Tamil said:
1 decade ago
If you want to multip[ly the theis type of big no follow the step:
1397 * 1397=?
1397*1400=1955800
and (1397+3=1400) so 1397*3=4191
1955800-4191=1951609
another example:
234*52
you can take 234*50=11700
and (52-2=50) so 234*2=468
11700+468=12168
1397 * 1397=?
1397*1400=1955800
and (1397+3=1400) so 1397*3=4191
1955800-4191=1951609
another example:
234*52
you can take 234*50=11700
and (52-2=50) so 234*2=468
11700+468=12168
(1)
AKSHAY said:
7 years ago
The multiplication of sum of digits = the some of digits of the answer.
example = 24*6 = 144 =1+4+4 = 9.
now 2+4 *6 = 36= 3+6=9.
So if the answer is given we can use this method.
Now, back to question.
1397*1397
1+3+9+7 * 1+3+9+7,
=2 * 2 = 4.
And, in option, 1951609 = 1+9+5+1+6+0+9 = 4.
example = 24*6 = 144 =1+4+4 = 9.
now 2+4 *6 = 36= 3+6=9.
So if the answer is given we can use this method.
Now, back to question.
1397*1397
1+3+9+7 * 1+3+9+7,
=2 * 2 = 4.
And, in option, 1951609 = 1+9+5+1+6+0+9 = 4.
(1)
Atif said:
7 years ago
1397 * 1397 = 1951609.
(1)
Ajith said:
8 years ago
@Isha.
Whether it is applicable to all type of problems like this?
Whether it is applicable to all type of problems like this?
Sowmi said:
8 years ago
Nice explanation @Rahul Jadhav.
Pratheev Kalyan said:
8 years ago
1397*1397=?
Since 1400*1400=1960000, so the result must be less than 1960000. By this, options c and d gets eliminated. Remaining is a and b.
The number 1397 is divisible by 11. So, the answer must also be divisible by 11. Thus option b(not divisible by 11) is eliminated and option a is the answer.
Since 1400*1400=1960000, so the result must be less than 1960000. By this, options c and d gets eliminated. Remaining is a and b.
The number 1397 is divisible by 11. So, the answer must also be divisible by 11. Thus option b(not divisible by 11) is eliminated and option a is the answer.
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