Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 53)
53.
(112 + 122 + 132 + ... + 202) = ?
Answer: Option
Explanation:
(112 + 122 + 132 + ... + 202) = (12 + 22 + 32 + ... + 202) - (12 + 22 + 32 + ... + 102)
![]() |
Ref: (12 + 22 + 32 + ... + n2) = | 1 | n(n + 1)(2n + 1) | ![]() |
|
6 |
= | ![]() |
20 x 21 x 41 | - | 10 x 11 x 21 | ![]() |
6 | 6 |
= (2870 - 385)
= 2485.
Discussion:
33 comments Page 4 of 4.
Jitu said:
1 decade ago
i also not got it......
even in formula the no. is divided by 2
even in formula the no. is divided by 2
Rajni Saini said:
1 decade ago
I can't understand, can you give any shortcut method to solve this problem plzzzz.
Sara said:
1 decade ago
I can't understand. Can anyone explain?
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