Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 61)
61.
When a number is divided by 13, the remainder is 11. When the same number is divided by 17, then remainder is 9. What is the number ?
Answer: Option
Explanation:
x = 13p + 11 and x = 17q + 9
13p + 11 = 17q + 9
17q - 13p = 2
| q = |
2 + 13p |
| 17 |
| The least value of p for which q = | 2 + 13p | is a whole number is p = 26 |
| 17 |
x = (13 x 26 + 11)
= (338 + 11)
= 349
Discussion:
47 comments Page 5 of 5.
Kanijv said:
1 decade ago
Here p=9 also works but the thing is that there is no option for that only p=26 we have the answer.
Shashank said:
1 decade ago
How the value of P becomes 26?
Vrunda said:
10 years ago
How is possible in p=26?
Rajani said:
9 years ago
How we get the value of p=26?
Please explain.
Please explain.
Sonu Shaw said:
9 years ago
How p = 26? Please explain that step.
Ravi said:
9 years ago
How are you taking p as 26? Please explain.
Shubham said:
9 years ago
@Ravi.
We have to satisfy the condition so that q should be greater than 1 that is why we take p =2, putting p =2 = 13 * 2 = 26 which is equal to p.
We have to satisfy the condition so that q should be greater than 1 that is why we take p =2, putting p =2 = 13 * 2 = 26 which is equal to p.
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