Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 110)
110.
A number was divided successively in order by 4, 5 and 6. The remainders were respectively 2, 3 and 4. The number is:
Answer: Option
Explanation:
4 | x z = 6 x 1 + 4 = 10 ----------- 5 | y -2 y = 5 x z + 3 = 5 x 10 + 3 = 53 ----------- 6 | z - 3 x = 4 x y + 2 = 4 x 53 + 2 = 214 ----------- | 1 - 4 Hence, required number = 214.
Discussion:
30 comments Page 3 of 3.
D Priya said:
8 years ago
@Sarthaksaxen.
This is successive division not normal division.
This is successive division not normal division.
Maahi said:
1 decade ago
If we take, x=4a+2 then a=5b+3 and b=6c+4. How does it come?
Bhavna said:
10 years ago
Not able to understand the solution elaborate it please.
Sanketh said:
5 years ago
I didn't get. Please, anyone, explain clearly.
(2)
Manikandan said:
9 years ago
How is the s value equal to 1? Please explain.
Bikas khan said:
8 years ago
I can't understand it please explain simple.
M.stoica said:
1 decade ago
214 divided by 5 how the remainder can be 3?
Dhanya said:
9 years ago
Can anyone elaborate it step by step?
Adithya Krishnan said:
9 months ago
Thanks for explaining the answer.
Debdas biswas said:
7 years ago
Thanks all for explaining this.
(1)
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