Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 110)
110.
A number was divided successively in order by 4, 5 and 6. The remainders were respectively 2, 3 and 4. The number is:
Answer: Option
Explanation:
4 | x z = 6 x 1 + 4 = 10 ----------- 5 | y -2 y = 5 x z + 3 = 5 x 10 + 3 = 53 ----------- 6 | z - 3 x = 4 x y + 2 = 4 x 53 + 2 = 214 ----------- | 1 - 4 Hence, required number = 214.
Discussion:
30 comments Page 2 of 3.
Debdas biswas said:
7 years ago
Thanks all for explaining this.
(1)
Tapan said:
7 years ago
I think it is right. Because 214 first divided by 4 then the quotient is 53 remainder is 2, then 53 is divided by 5 then the quotient is 10 remainder is 3, and then 10 is divided by 6 then the reminder is 4.
(1)
Shadab said:
8 years ago
The Number is 4 5 6 And their Remainder in 2 3 4 On just multiplying we got the answer like this [(6+4) * (5)+(3) * (4)+(2)] = 214.
(1)
Adithya Krishnan said:
9 months ago
Thanks for explaining the answer.
Aman said:
1 decade ago
Not able to understand this question, what is asking, please discuss.
D Priya said:
8 years ago
@Sarthaksaxen.
This is successive division not normal division.
This is successive division not normal division.
Bikas khan said:
8 years ago
I can't understand it please explain simple.
Vijay mittal said:
9 years ago
In this question 214 is correct if only 214 is divided by 4, 5, 6. Orderly using the quotient of the previous solution. But in question, there is no explanation about this.
Manikandan said:
9 years ago
How is the s value equal to 1? Please explain.
Vivek gupta said:
9 years ago
Wrong answer.
How can remainder will be 3 when 214 is divided by 5?
The Correct answer should be 60k-2.
Where k is any integer.
How can remainder will be 3 when 214 is divided by 5?
The Correct answer should be 60k-2.
Where k is any integer.
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