Aptitude - Numbers - Discussion

@Sunny

462 is not divisible by 4.

The logic is some what like this...If a number is divisible by p and q then its also divisible by p*q(product of two nos),to the condition that p and q are co-primes..extending the rule to one more level..!!

You have told that the number divisible by all the three number 4, 3 and 11, then the number is divisible by 132 also.

but,462 is divisible by 4,3 and 11,so according to your logic,so why 462 is not in the category that divisible by 132.WHY? please reply very soon

If a number "A" is divisible by all factors of another number say "B", then "A" is divisible by "B"
thats the logic

example factors of 6= 2*3

any number that is divisible by both 2 and 3 will be divisible by 6. always
in this quetsion we have factorized 132 in to 4*3*11 so that we can check whether all numbers are divisible by them.. if yes then the number is divisible by 132.

ps: shortcut, u need to learn the divisibility rules for 11 and 3, google them

Logic is not clearly explain the answer.

Please explain me in easiest way.

I need a shortcut method to solve this problem please.

Thats is nothing but the 132 is the multiplication of 11*3*4 the no which are divisible by these 3 are the answers.

All the numbers are even, so not necessary to take 2 as a to check. By taking the minimum nos to use, we split 132 as 4*3*11

Why have we taken only 4, 3, 11 why can't we take 2?

Why can't we take 2*2*3*11 ? Why it is only 4*3*11 ?

These three numbers are the LCM of the Given number i.e. 132.