Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 6)
6.
How many of the following numbers are divisible by 132 ?
264, 396, 462, 792, 968, 2178, 5184, 6336
264, 396, 462, 792, 968, 2178, 5184, 6336
Answer: Option
Explanation:
132 = 4 x 3 x 11
So, if the number divisible by all the three number 4, 3 and 11, then the number is divisible by 132 also.
264 
11,3,4 (/)
396 11,3,4 (/)
462 11,3 (X)
792 11,3,4 (/)
968 11,4 (X)
2178 11,3 (X)
5184 3,4 (X)
6336 11,3,4 (/)
Therefore the following numbers are divisible by 132 : 264, 396, 792 and 6336.
Required number of number = 4.
Discussion:
61 comments Page 4 of 7.
Shiv said:
9 years ago
I don't understand why only we take 4, 3 and 11.
How I would be wrong if I take 2*11*3?
How I would be wrong if I take 2*11*3?
(3)
Lokesh said:
1 year ago
We can tell this as prime factorization. So, the prime factors of 132 is 4, 11, 3.
(4)
Jahanzeb said:
1 decade ago
Logic is not clearly explain the answer.
Please explain me in easiest way.
Please explain me in easiest way.
AAmin said:
1 decade ago
@Siranjeevi. If you go by that method answer comes 7 whereas answer is 4.
Adil said:
9 years ago
This is the wrong answer. In this logic, 462 can also divide by 4, 3, 11.
Rajat tamoli said:
6 years ago
Factor found of 132 = 2*2*11*3.
So that's the reason for taking 4*11*3.
So that's the reason for taking 4*11*3.
(2)
Silent reader said:
6 months ago
I think the answer is 7.
Only 968 & 5184 are not divisible by 132.
Only 968 & 5184 are not divisible by 132.
(3)
Ravip said:
9 years ago
Can you please explain me what is the divisibility condition for 11.
Rushikesh said:
7 years ago
What is the divisibility property of 11?
Please, anyone, explain.
Please, anyone, explain.
Lalitha said:
7 years ago
@All.
Here, We can take 6, but again 6 having the factors of 2*3.
Here, We can take 6, but again 6 having the factors of 2*3.
(5)
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