Aptitude - Numbers - Discussion

You can't use the 11*6*2 because the rule is that the pairings have to be coprimes with the exception of prime numbers.
11, 3, 4 don't have any factors with each other.

Thank you senthi. I agree with your answer.

These three numbers are the LCM of the Given number i.e. 132.

Why can't we take 2*2*3*11 ? Why it is only 4*3*11 ?

Why have we taken only 4, 3, 11 why can't we take 2?

All the numbers are even, so not necessary to take 2 as a to check. By taking the minimum nos to use, we split 132 as 4*3*11

Thats is nothing but the 132 is the multiplication of 11*3*4 the no which are divisible by these 3 are the answers.

I need a shortcut method to solve this problem please.

Logic is not clearly explain the answer.

Please explain me in easiest way.

If a number "A" is divisible by all factors of another number say "B", then "A" is divisible by "B"
thats the logic

example factors of 6= 2*3

any number that is divisible by both 2 and 3 will be divisible by 6. always
in this quetsion we have factorized 132 in to 4*3*11 so that we can check whether all numbers are divisible by them.. if yes then the number is divisible by 132.

ps: shortcut, u need to learn the divisibility rules for 11 and 3, google them