Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 6)
6.
How many of the following numbers are divisible by 132 ?
264, 396, 462, 792, 968, 2178, 5184, 6336
264, 396, 462, 792, 968, 2178, 5184, 6336
Answer: Option
Explanation:
132 = 4 x 3 x 11
So, if the number divisible by all the three number 4, 3 and 11, then the number is divisible by 132 also.
264 
11,3,4 (/)
396 11,3,4 (/)
462 11,3 (X)
792 11,3,4 (/)
968 11,4 (X)
2178 11,3 (X)
5184 3,4 (X)
6336 11,3,4 (/)
Therefore the following numbers are divisible by 132 : 264, 396, 792 and 6336.
Required number of number = 4.
Discussion:
61 comments Page 2 of 7.
Chethanya said:
1 decade ago
Why can't we do it in this method.
264/132 = 2.
396/132 = 3.
462/132 = 3.5.
792/132 = 6.
968/132 = 7.31.
2178/132 = 16.5.
5184/132 = 39.27.
6336/132 = 48.
BY seeing above 4 numbers are divisible by 132.
264/132 = 2.
396/132 = 3.
462/132 = 3.5.
792/132 = 6.
968/132 = 7.31.
2178/132 = 16.5.
5184/132 = 39.27.
6336/132 = 48.
BY seeing above 4 numbers are divisible by 132.
Mufariq said:
1 decade ago
Dear all its so easy.
See to all which number is divide complete on 132:264, 396, 462, 792, 968, 2178, 5184, 6336 and don't leave no reminder.
That is,
264/132=2, 396/132=21, 462/132=21.4 and so on.
See to all which number is divide complete on 132:264, 396, 462, 792, 968, 2178, 5184, 6336 and don't leave no reminder.
That is,
264/132=2, 396/132=21, 462/132=21.4 and so on.
Mahalakshmi V said:
1 month ago
My point of view divisible of 132 is 2*6*11.
Then, I follow the these divisible numbers I got the answer 6.
Because 6 numbers are divisible bye 132.
968 and 5184 are not divisible bye 132.
Then, I follow the these divisible numbers I got the answer 6.
Because 6 numbers are divisible bye 132.
968 and 5184 are not divisible bye 132.
(1)
Anvesha said:
9 years ago
@Koala,
I guess you missed out on the fact that we in here are talking about co-primes while 4 and 2 don't happen to be co-prime factors. 88 = 8 * 11.
And 9988 is not divisible by 8.
I guess you missed out on the fact that we in here are talking about co-primes while 4 and 2 don't happen to be co-prime factors. 88 = 8 * 11.
And 9988 is not divisible by 8.
Somanath dash said:
2 years ago
But if we consider 132=11*6*2.
Then the numbers divisible by 11, 6, 2 are 396, 462, 792, 2178, and 6336 tell me then why the answer is not 5 instead of 4 anyone please tell me.
Then the numbers divisible by 11, 6, 2 are 396, 462, 792, 2178, and 6336 tell me then why the answer is not 5 instead of 4 anyone please tell me.
(16)
Koala said:
9 years ago
@Yuvaraj.
I don't think the given solution I applicable for every number.
Eg: 9988 is divisible by all the factors of 88 (4 x 2 x 11).
But then too it is not divisible by 88.
I don't think the given solution I applicable for every number.
Eg: 9988 is divisible by all the factors of 88 (4 x 2 x 11).
But then too it is not divisible by 88.
Kalai said:
6 years ago
@Rushikesh.
Divisibility rule for 11: Difference between the sum of digits at odd places and sum of digits at even places is either 0 or a number that is divisible by 11.
Divisibility rule for 11: Difference between the sum of digits at odd places and sum of digits at even places is either 0 or a number that is divisible by 11.
(6)
Jake said:
10 years ago
I just got confused with the logic, there are many answers to this not one. I agree with dividing each by 132 to get a whole number with no reminder. Its more satisfying.
Supriya said:
1 decade ago
@Siranjeevi:
As per your method, after adding it gets 12 18 12 18 23 18 18 18.
So except 12 nothing is divide by 6.
Is there any other fast method?
As per your method, after adding it gets 12 18 12 18 23 18 18 18.
So except 12 nothing is divide by 6.
Is there any other fast method?
Amulak said:
1 decade ago
Hey guys.
First we take coprime factors, that's why we take 4,3,and 11 and not 2.
coprime nos are those no whose HCF is 1.
Hope now it is clear.;)
First we take coprime factors, that's why we take 4,3,and 11 and not 2.
coprime nos are those no whose HCF is 1.
Hope now it is clear.;)
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