Aptitude - Numbers - Discussion

My point of view divisible of 132 is 2*6*11.

Then, I follow the these divisible numbers I got the answer 6.

Because 6 numbers are divisible bye 132.

968 and 5184 are not divisible bye 132.

Factor found of 132 = 2*2*11*3.
So that's the reason for taking 4*11*3.

462 is also divisible by 11 and gives 42 so why we won't take it?

It's answer should be 5.

Dividing each of the numbers with 132 directly is a lengthy and difficult process. So we take coprime factors, i.e 4, 3, and 11
(That's nothing but 132 is the multiplication of 11*3*4 , so the no's which are divisible by these 3 are also divisible by 132)
Divisibility rule for 11 : Difference between sum of digits at odd places and sum of digits at even places is either 0 or a number that is divisible by 11.
Divisibility rule for 3 : sum of digits is divisible by 3.
Divisibility rule for 4 : last 2 digits is divisible by 4.
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Round 1 : Just by seeing we can clearly tell that 264, 396, 462,792, 6336 are divisible by 11.
Round 2 : Now we have to check if above 5 numbers are also divisible by 3 and 4.
But 462 is not divisible by 4, because the last 2 digits ie 62 is not divisible by 4. Rest 4 of these numbers above are divisible by both 3 and 4.

So, the final answer is 4.

Very Helpful. Thanks.

You can't use the 11*6*2 because the rule is that the pairings have to be coprimes with the exception of prime numbers.
11, 3, 4 don't have any factors with each other.

Please explain the answer shortly.

What does it mean the required number of number is 4?

11, 3, 4 is H.C.F of 132 that's why, we take it.

Can you please explain me what is the divisibility condition for 11.