Aptitude - Numbers - Discussion

462 is also divisible by 11 and gives 42 so why we won't take it?

It's answer should be 5.

My point of view divisible of 132 is 2*6*11.

Then, I follow the these divisible numbers I got the answer 6.

Because 6 numbers are divisible bye 132.

968 and 5184 are not divisible bye 132.

Dividing each of the numbers with 132 directly is a lengthy and difficult process. So we take coprime factors, i.e 4, 3, and 11
(That's nothing but 132 is the multiplication of 11*3*4 , so the no's which are divisible by these 3 are also divisible by 132)
Divisibility rule for 11 : Difference between sum of digits at odd places and sum of digits at even places is either 0 or a number that is divisible by 11.
Divisibility rule for 3 : sum of digits is divisible by 3.
Divisibility rule for 4 : last 2 digits is divisible by 4.
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Round 1 : Just by seeing we can clearly tell that 264, 396, 462,792, 6336 are divisible by 11.
Round 2 : Now we have to check if above 5 numbers are also divisible by 3 and 4.
But 462 is not divisible by 4, because the last 2 digits ie 62 is not divisible by 4. Rest 4 of these numbers above are divisible by both 3 and 4.

So, the final answer is 4.

What does it mean the required number of number is 4?

Very Helpful. Thanks.

Please explain the answer shortly.

Smart thinking and superb explanation @Chethanya.

Here answer is 4. But according to @Siranjeevi 6, can you clarify?

11, 3, 4 is H.C.F of 132 that's why, we take it.

=132/11=22.

=132/4=33.

=132/3=44.