Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 3)
3.
It is being given that (232 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
(216 + 1)
(216 - 1)
(7 x 223)
(296 + 1)
Answer: Option
Explanation:

Let 232 = x. Then, (232 + 1) = (x + 1).

Let (x + 1) be completely divisible by the natural number N. Then,

(296 + 1) = [(232)3 + 1] = (x3 + 1) = (x + 1)(x2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N.

Discussion:
137 comments Page 11 of 14.

Shirisha said:   9 years ago
I understand this. But I want simple method.

Pranshu said:   9 years ago
Why not option A? Explain.

Sajal said:   9 years ago
I didn't understand the last step. Please explain it.

Apsana said:   9 years ago
I can't understand this please explain this in a simply way.

Sajid said:   9 years ago
I don't understand. Please, someone explain me.

Saruu said:   9 years ago
Can anyone give a simple method to explain this?

Deva said:   8 years ago
I don't understand the solution. Please, someone explain me.

Kranthi said:   8 years ago
Remember the condition that (x^n+1^n) is divisible by (x+1). Given number (2^32+1) is divisor. He said which of the following number is divided by this number i.e. (2^32+1). The dividend should be in the form of (x^n+1^n). Let x=2^32(from divisor).

Substituae it in dividend. [(2^32)^n+1^n].

Substitube n= 1,3,5,... 4 th option suits when n=3.

Aravinth Kumar said:   8 years ago
@Kishore Sulthana.

Good explanation. I can understand it now.

Lupu gogoi said:   8 years ago
We are finding the answer. We don't know what is the answer above this problem. Then how to you directly put the answer 2^96+1.

How you know the answer is that? If the problem given you another then how to you solve that. Please explain.


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