Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 58)
58.
On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is:
10
11
12
13
Answer: Option
Explanation:

Clearly, (2272 - 875) = 1397, is exactly divisible by N.

Now, 1397 = 11 x 127

The required 3-digit number is 127, the sum of whose digits is 10.

Discussion:
34 comments Page 4 of 4.

Geetha said:   1 decade ago
Please explain me how you get 1397 is 11 & 127?

Sanjali Jha said:   1 decade ago
Lets take the remainder as x,

2272-x is the quotient which is divisible by n.

875-x is the quotient which is divisible by n.

[2272-x]-[875-x] = a number which is divisible by n.

= 1397.

The factors of 1397 are 11 and 127.

127 is n as it is a three digit number and fills all conditions.

1+2+7 = 10.

10 is the answer.

Faizal said:   1 decade ago
hello buddys!

I think the following could be one of the methods:

we know, dividend=divisor*quosent+remainder
divisor=d,quosen=1(if not given assume it to be 1)+remainder=r

so, 2272=d*1+r
875=d*1+r
since remainder are equal from the question,
r=2272-d -equ1
r=875-d -equ2
equ=equ2

2272-d=875-d
we get 1397 this our N.and sum of the digits 20.
becoz we r dealing with two equ same remainder, so divide it by 2.
i.e 20/2= 10.

I dont know whether is it wright but any ways am getting the answer.

Swatantra said:   1 decade ago
Sorry ! I couldn't get it.......... please explain it in another way.


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