Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 58)
58.
On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is:
10
11
12
13
Answer: Option
Explanation:

Clearly, (2272 - 875) = 1397, is exactly divisible by N.

Now, 1397 = 11 x 127

The required 3-digit number is 127, the sum of whose digits is 10.

Discussion:
34 comments Page 4 of 4.

Silgrik K Sangma said:   4 years ago
Where did 11 and 127 comes from?

Please explain.
(9)

AKPARIDA said:   4 years ago
Here we need to find the sum of the digits of the required 3-digit number.
As the given two numbers when divided by 3-digit numbers give the same remainder then that means when we find the difference between them then that difference will be divisible by that three-digit number.

So, we will first find the difference between the given numbers, i.e. 2272 and 875.

Difference=2272-875=1397 --->(1)

1397 will be divisible by a three-digit number i.e. N.
.
We know that the factors of the number 1397 are 11 and 127.
The only three-digit number which has a factor of 1397 is 127.
So, we can say that the value of the three-digit number i.e. N.
It's equal to 127.
Now, we will find the sum of the digits of the N.
The sum of the digits of N.
=1+2+7=10.
Hence, the correct option is option A.
(11)

Mathu said:   4 years ago
@All.

Here is the solution.

2272-R=0(mod N).
875-R=0(mod N).
2272-875=0(mod N).
1397=0(mod N).

So, any factor of 1397 can be the answer for N which 127 will be correct according to the question given (3digit numbers).

1+2+7=10.
(5)

SOURJYA MONDAL said:   2 years ago
2272 - 875 = 1397 which is divisible by 11.
i.e. , 1397 = 11 X 127.
so, 1+2+7 = 10.
(4)


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