Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 58)
58.
On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is:
Answer: Option
Explanation:
Clearly, (2272 - 875) = 1397, is exactly divisible by N.
Now, 1397 = 11 x 127
The required 3-digit number is 127, the sum of whose digits is 10.
Discussion:
34 comments Page 3 of 4.
Swatantra said:
1 decade ago
Sorry ! I couldn't get it.......... please explain it in another way.
Himanshu said:
1 decade ago
@Shreyank by adding the digits of 127 (i e. , the 3-digit number).
Sssddzs said:
7 years ago
@Jatin.
Is it applicable to all problems? How did you take 3?
Is it applicable to all problems? How did you take 3?
Jeff said:
6 years ago
Why do we subtract the two numbers, here? Please tell me.
Jatin said:
10 years ago
Here is an shortcut:
= 2+2+7+2-8+7+5 = 7.
= 7+3 = 10.
= 2+2+7+2-8+7+5 = 7.
= 7+3 = 10.
Shreyank said:
1 decade ago
We can 11*127 so we can get 1397.
But how we get 10.
But how we get 10.
Geetha said:
1 decade ago
Please explain me how you get 1397 is 11 & 127?
Silgrik K Sangma said:
4 years ago
Where did 11 and 127 comes from?
Please explain.
Please explain.
(9)
Queeen said:
5 years ago
2272-875 = 1397.
1397/11 = 127.
1+2+7 = 10.
1397/11 = 127.
1+2+7 = 10.
Janaki said:
1 decade ago
Why we are factorizing 1397?
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