Aptitude - Decimal Fraction - Discussion

Discussion Forum : Decimal Fraction - General Questions (Q.No. 9)
9.
(0.1667)(0.8333)(0.3333) is approximately equal to:
(0.2222)(0.6667)(0.1250)
2
2.40
2.43
2.50
Answer: Option
Explanation:
Given expression
= (0.3333) x (0.1667)(0.8333)
(0.2222) (0.6667)(0.1250)
= 3333 x
1 x 5
6 6
2222
2 x 125
3 1000
= 3 x 1 x 5 x 3 x 8
2 6 6 2
= 5
2
= 2.50
Discussion:
43 comments Page 4 of 5.

Leul said:   8 years ago
Any other simple method?

Varsha said:   7 years ago
Thanks @Sai Manohar.

Selva said:   7 years ago
All are multiplied by 10000 so that they can become whole numbers.

Take the first two digits 16*83*33=43824.
Take denominator first two digits 22*66*12=17424.
So, 43824/17424 = 2.51.
(3)

Shubham said:   7 years ago
I am not getting the solution of this. Please, anyone explain me clearly.

Varun said:   6 years ago
Thanks @Satish.

Kishan said:   5 years ago
For getting 0.16667 as 1/6, we can do:

0.1667*10 = 1.6667.

Now, 1.6667 is equal to 1+ 0.6667, we know how to convert 0.6667 to a fraction.
0.6667 = 6/9 => 2/3.

Therefore, we have 1+ 0.667 => 1+(2/3)=> 5/3,

But remember we multiplied by 10 in the beginning, so we divide by 10 to nullify the change.
Therefore (5/3)/10 => 1/6.
(1)

Joby George said:   5 years ago
Hi all, from my understanding, the conversion to a fraction is actually used for non-terminating recurring decimals, however, that is not the case here, all are terminating decimals, we can convert them only like, 0.67 = 67/100.

Leena said:   4 years ago
How it becomes 3333/2222 to 3/2? Pleas tell me.
(2)

Saptarshi Ghosh said:   4 years ago
it's basically a bar concept. That is 0.22222 can be written as 0.2 and infraction it can be written as 2/9.

The formula is (number without decimal - non-repeating numbers)/put 9's the number of repeating numbers and 0's the number of non-repeating numbers.

Suppose, 0.35232323 it can be written as (3523 - 35)/(9900).
Put that in that problem and you are good to go.
(6)

Pallavi said:   4 years ago
How 1/6, 2/3, 5/6 come? Please explain.
(3)


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